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Tasya [4]
3 years ago
5

Marcus gathered data on the average time it takes for students to get to school each morning. Of all the responses, 10 people sa

id 15 minutes, 18 people said 30 minutes, and 12 people said 25 minutes.
If the standard deviation of the population is 5.64 minutes, what is the 95% confidence interval for the population mean?
Mathematics
1 answer:
sveticcg [70]3 years ago
5 0

Answer:

24.75, 1.75

Step-by-step explanation:

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The moon is about 240000 miles from earth.What is the distance written as a whole number multiplied by a power of ten
Sauron [17]
A whole number? ok. 24x10^4. usually though you would use standard form so it would be 2.4x10^5
5 0
3 years ago
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What is the length of line segment PQ? If you can please explain, thanks.
nydimaria [60]

Given:

Tangent segment MN = 6

External segment NQ = 4

Secant segment NP =x + 4

To find:

The length of line segment PQ.

Solution:

Property of tangent and secant segment:

If a secant and a tangent intersect outside a circle, then the product of the secant segment and external segment is equal to the product of the tangent segment.

\Rightarrow NQ\times NP = MN^2

\Rightarrow 4\times (x+4) = 6^2

\Rightarrow 4x+16 = 36

Subtract 16 from both sides.

\Rightarrow 4x+16-16 = 36-16

\Rightarrow 4x =20

Divide by 4 on both sides.

$\Rightarrow\frac{4x}{4}=\frac{20}{4}

\Rightarrow x = 5

The length of line segment PQ is 5 units.

5 0
4 years ago
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Up or down and maximum or minimum
just olya [345]
Down and maximum I think I know down is right for sure but I’m not sure about the other one
7 0
3 years ago
PLZ HELP 25 POINTS Solve for x show your work<br><br>A. x 5 4 6<br><br>B. 5 3 x 4
frosja888 [35]

The two lines start at the same point outside the circle, using the intersecting Secants theorem, When you multiply the two dims for each line together, they are equal

For A:

5 * (5+x) = 6 * (6+4)

25 + 5x = 60

5x = 35

x = 35/5

x = 7

For B:

5 * (5+ 3) = 4 * ( 4+x)

40 = 16 + 4x

4x = 24

x = 24/4

x = 6

8 0
3 years ago
There are 12 people on a basketball team. How many different five-person starting lineups can be chosen
FinnZ [79.3K]
12!/5!7! = (12*11*10*9*8)/(5*4*3*2*1)=792


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3 years ago
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