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monitta
3 years ago
8

Suppose 12% of students are veterans. From a sample of 263 students, how unusual would it be to have less than 22 veterans?

Mathematics
1 answer:
kkurt [141]3 years ago
7 0

Answer:

Yes, both np and n(1-p) are ≥ 10

Mean = 0.12 ; Standard deviation = 0.02004

Yes. There is a less than 5% chance of this happening by random variation. 0.034839

Step-by-step explanation:

Given that :

p = 12% = 0.12 ;

Sample size, n = 263

np = 263 * 0.12 = 31.56

n(1 - p) = 263(1 - 0.12) = 263 * 0.88 = 231.44

According to the central limit theorem, distribution of sample proportion approximately follow normal distribution with mean of p = 0.12 and standard deviation sqrt(p*(1 - p)/n) = sqrt (0.12 *0.88)/n = sqrt(0.0004015) = 0.02004

Z = (x - mean) / standard deviation

x = 22 / 263 = 0.08365

Z = (0.08365 - 0.12) / 0.02004

Z = −1.813872

Z = - 1.814

P(Z < −1.814) = 0.034839 (Z probability calculator)

Yes, it is unusual

0.034 < 0.05 (Hence, There is a less than 5% chance of this happening by random variation.

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Problem 5

d = 29 = diameter

r = d/2 = 29/2 = 14.5 = radius

SA = surface area of sphere

SA = 4*pi*r^2

SA = 4*pi*(14.5)^2

SA = 841pi

SA = 841*3.14

SA = 2,640.74 square inches

To convert from square inches to square feet, we divide by 144. This is because 12^2 = 144.

2,640.74 square inches = (2,640.74)/144 = 18.3 sq ft

<h3>Answer: 18.3 square feet (approximate)</h3>

=====================================

Problem 6

d = 10.7 = diameter

r = d/2 = 10.7/2 = 5.35 = radius

L = 22.3 = slant height

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SA = pi*r^2 + pi*r*L

SA = pi*(5.35)^2 + pi*5.35*22.3

SA = 147.9275pi

SA = 147.9275*3.14

SA = 464.49235

<h3>Answer:  464.49235 square cm (approximate)</h3>
8 0
3 years ago
What is the answer to number nine also how do I solve for it? Thanks:)
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Well the whole ratio is 14 sooooo
98 ÷ 14 =7

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