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monitta
3 years ago
8

Suppose 12% of students are veterans. From a sample of 263 students, how unusual would it be to have less than 22 veterans?

Mathematics
1 answer:
kkurt [141]3 years ago
7 0

Answer:

Yes, both np and n(1-p) are ≥ 10

Mean = 0.12 ; Standard deviation = 0.02004

Yes. There is a less than 5% chance of this happening by random variation. 0.034839

Step-by-step explanation:

Given that :

p = 12% = 0.12 ;

Sample size, n = 263

np = 263 * 0.12 = 31.56

n(1 - p) = 263(1 - 0.12) = 263 * 0.88 = 231.44

According to the central limit theorem, distribution of sample proportion approximately follow normal distribution with mean of p = 0.12 and standard deviation sqrt(p*(1 - p)/n) = sqrt (0.12 *0.88)/n = sqrt(0.0004015) = 0.02004

Z = (x - mean) / standard deviation

x = 22 / 263 = 0.08365

Z = (0.08365 - 0.12) / 0.02004

Z = −1.813872

Z = - 1.814

P(Z < −1.814) = 0.034839 (Z probability calculator)

Yes, it is unusual

0.034 < 0.05 (Hence, There is a less than 5% chance of this happening by random variation.

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Answer:

A

Step-by-step explanation:

Find AB using the Law of Sine:

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Thus:

\frac{AB}{sin(40)} = \frac{47}{sin(103)}

Multiply both sides by sin(40)

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olya-2409 [2.1K]

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Answer:

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Step-by-step explanation:

Many people find it easier to factor out -1, then do the addition. The fractions need a common denominator before they can be added. A suitable denominator that is a multiple of both 4 and 8 is 8.

The fraction 1/4 = (1/4)(2/2) = (1·2)/(4·2) = 2/8.

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So, the problem can be rewritten as ...

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3 years ago
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Dafna11 [192]
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