The number in the "tens" place is eight (8).
Answer:
a) x = {-2, 1, 3} are the zeros
b) y = (x +2)(x -1)(x -3)
c) y = x^3 -2x^2 -5x +6
Step-by-step explanation:
a) The zeros are the values of x where the graph crosses y=0. Those values are x = -2, x = 1, x = 3.
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b) If "a" is a zero, then (x-a) is a factor. The factored polynomial is ...
y = (x +2)(x -1)(x -3)
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c) This can be multiplied out using the distributive property several times.
y = (x +2)(x(x -3) -1(x -3))
= (x +2)(x^2 -3x -x +3)
= (x +2)(x^2 -4x +3)
= x(x^2 -4x +3) +2(x^2 -4x +3)
= x^3 -4x^2 +3x +2x^2 -8x +6
y = x^3 -2x^2 -5x +6
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The supplied graph apparently scales this vertically by a factor of 1/2, since its y-intercept is at (0, 3), not (0, 6).
Given:
In triangle GHI, h = 300 inches, G=30° and H=29º.
To find:
The length of i.
Solution:
We have, G=30° and H=29º.
Using angle sum property, we get





According to Law of sines,

Using Law of sines, we get



Multiply both sides by 0.8572.



Therefore, the length of i is about 530 inches.
1) Area = (b*h)/2 = (9*5)/2 = 45/2 = 22.5 (Letter A)
2) Area = b*h = 8*14 = 112 (Letter D)
3) Surface area of a prism is SA=2B+ph (B = area of the base, p = perimeter of the base, h = height)
B = 15 * 5 = 75 cm^2
p = 15 + 5 = 20 cm
SA = 2*75 + 20*7 = 150 + 140 = 290 (G)
4) V = (B*H*L)/2 = (15*7*5)/2 = 525/2 = 262.5 cm^3 (G)
5) V = 9^3 = 81 cm^3 worth of wrapping (A)
6) V = (B*H*L)/2 = (13*6*8)/2 = 312 cube feet (J)
It gave me ADGGAJ. I don't know if this is right, but I atleast tried to do something, right?