A ) v = v o - a t
0 = 22 - a · t
a · t = 22
d = v o · t - a t²/2
0.04 = 22 t - 22 t / 2
0.04 = 11 t
t = 0.04 : 11 = 0.003636 s
a = 22 / t
a = 6050 m/s²
F = m · a = 0.09 kg · 6050 m/s²
F ( target→arrow) = - 544.5 N
b ) F ( arrow→target ) = 544.5 N
c ) If the speed was doubled: v = 44 m/s;
F = a m
a = 6050 m/s²
a · t = 44
t = 6050 : 0.04
t = 0.007272 s
d = 44 t - 44 t/2 = 22 t
d = 22 · 0.007272
d = 0.16 m = 16 cm
Answer:
The heat may have stopped being added, because the heat is exactly what is causing the change. There are horizontal lines because of that, and when the heat resumes, the line peaks up.
Explanation:
<span>To find the amount of work done by a force acting on a moving object, we can use this simple equation:
W = F * d * cos(theta)
W is Work
F is the force
d is the distance the object moves
theta is the angle between the force vector and the direction of motion
We know that (F * d) is 190 joules. We can find the work done when the angle is 56°.
W = F * d * cos(theta)
W = (190 J) * cos(56°)
W = 106 J
At an angle of 56°, the work done by the force is 106 joules.</span>
Heat it until it evaporates(Gas) :3
Or freeze it until its ice.(Solid)
its already a liquid normally
Unless you mean like separate the noodles from the broth, in that case use a drainer :'D Jk. I suck at smart stuff.
