What would happen to the seasons if the Earth’s tilt was only 10 degrees and why? What about 50 degrees and why?
1 answer:
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Answer:
0.082 T
Explanation:
Given:
Frequency of the generator (f) = 60.0 Hz
Maximum emf of the generator (E) = 5200 V
Number of turns (N) = 180
Area per turn (A) = 0.94 m²
Magnetic field magnitude (B) = ?
We know that, the angular frequency of the generator is given as:
Plug in the value of 'f' and solve for 'ω'. This gives,
Now, the maximum emf of the generator is given by the formula:
Rewriting in terms of magnetic field, 'B', we get:
Plug in the given values and solve for 'B'. This gives,
Therefore, the magnitude of the magnetic field in which the coil rotates is 0.082 T.
Answer:
(a) The package lands 682 meters horizontally ahead from the point the package was dropped from the plane
(b) The horizontal component = 39.0 m/s
The vertical component = 171.55 m/s
(c) The angle of impact is 77.19°
Explanation:
The parameters given are;
Velocity of the plane, vₓ = 39.0 m/s
Height of the plane above the ground, h = 1.50 × 10² m = 1,500 m
(a) The time, t, before the package hits the ground when dropped from the plane is given by the relation;
h = u·t + 1/2×g×t²
Where:
g = Acceleration due to gravity = 9.81 m/s²
u = Initial vertical velocity = 0 m/s
Hence;
1500 = 0×t + 1/2 × 9.81 × t² = 4.905·t²
∴ t = √(1500/4.905) = 17.49 s
The horizontal distance the package travels before landing = 17.49 × 39 ≈ 682 m
The package lands 682 meters horizontally ahead from the point the package was dropped from the plane
(b) The vertical velocity, , of the package just before landing is given by the relation;
² = u² + 2·g·h
u = 0 m/s
∴ ² = 0 + 2×9.81×1500 = 29430 m²/s²
= √29430 = 171.55 m/s
Hence the horizontal component = 39.0 m/s
The vertical component = 171.55 m/s
(c) The angle of impact, θ, is given as follows;
∴ θ = tan⁻¹(4.4) = 77.19°.