In short, part A is from 1pm to 6pm, well, that's 5 hours, namely t = 5.
and part B is t = 12, so we simply plug those values in, nothing to it.
and round it up as needed if any.
Answer: (3x−2)(4x−1)
Step-by-step explanation:
<em>Start factoring with -11x.</em>
12x^(2)-11x+2
12x2+(−8−3)x+2
12x2+(−8x−3x)+2
12x2−8x−3x+2
<em>Factor the highest common denominator of each group.</em>
<em>Group the first two terms and the last two.</em>
(12x2−8x)+(−3x+2)
<em>Factor the highest common denominator (MCD) of each group.</em>
<em>4x(3x−2)−(3x−2)</em>
<em>Factoring the highest common denominator 3x−2.</em>
(3x−2)(4x−1)
Answer:
364/27
Step-by-step explanation:
9, 3, 1, ... is a geometric sequence with common ratio r = 1/3.
The nth term is a1rn-1.
If a1rn-1 = 1/27, then 9(1/3)n-1 = 1/27
32(3-1)n-1 = 3-3
3231-n = 3-3
33-n = 3-3
3-n = -3
n = 6
The sum, Sn, of the first n terms of a geometric sequence is given by Sn = a1(1 - rn) / (1 - r).
So, 9 + 3 + 1 + ... + 1/27 = S6 = 9(1 - (1/3)6) / (1 - 1/3)
= 9(1 - 1/729) / (2/3)
= (27/2)(728/729) = 364/27
Answer:
Option (C)
Step-by-step explanation:
From the graph attached,
In ΔABC and ΔA'B'C',
∠A ≅ ∠A'
∠B ≅ ∠B'
Therefore, ΔABC ~ ΔA'B'C'
Corresponding sides of these triangles will be proportional.
Therefore, ratio of the sides, AC : A'C' = 1 : 3 shows that image triangle A'B'C' is a dilated form of pre-image ABC with a scale factor of 3.
Option (C) will be the correct option.
