Prove identity tan 3x−tan 2x−tanx = tan 3xtan 2xtanx
1 answer:
Tan ( a + b ) = [ tan a + tan b ] / [ 1 - (tan a)*(tan b) ];
let be a = 2x and b = x;
=> tan 3x = [ tan 2x + tan x ] / [ 1 - (tan 2x)*(tan x) ] => (tan 3x)*[ 1 - (tan 2x)*(tan x) ] =
tan 2x + tan x => tan3x - tan 3xtan 2xtanx = tan 2x + tan x => <span> tan 3x−tan 2x−tanx = tan 3xtan 2xtanx.</span><span />
You might be interested in
Answer:
72.54
Step-by-step explanation:
Use formula for trapezoid: a+b/2 * h
Answer: is c 3/2
Step-by-step explanation:
Answer 25 r 32
Step by step: hopefully you can see the photo
Answer:
No it's not proportional