Split the second term in
2x squared -5x + 3 into two terms
2x squared - 2x - 3x + 3
Factor out common terms and last two terms
2x(x-1) -3 (x-1)
Factor out the common term x - 1
ANSWER: (x-1) (2x-3)
Answer:
Step-by-step explanation:
hello :
3x − 2y = −9 ...(*)
4x + 3y = 22...(**)
multiply (*) by 3 and(**) by 2 you have : 9x-6y = -27
8x+6y =44
add this equations : 17x = 17 so : x=1
put this value in : 8x+6y=44
8(1)+6y=44
6y=36
y=6
one solution : (1 ; 6)
Subtract 3 from both sides
x/5= 3
Multiply both sides by 5
x=15
Final answer: x=15
Answer:
Step-by-step explanation:
Suppose x and y are nonzero vectors in an inner product space.
Let us assume that x and y are orthogonal
i.e. innter product is 0.
This implies dot product of x and y is 0
Then x.y =0
i.e. ![x^2+y^2 +2x.y = x^2+y^2-2x.y\\||x+y||=||x-y||](https://tex.z-dn.net/?f=x%5E2%2By%5E2%20%2B2x.y%20%3D%20x%5E2%2By%5E2-2x.y%5C%5C%7C%7Cx%2By%7C%7C%3D%7C%7Cx-y%7C%7C)
Proved
Converse part:
Let ![||x+y||=||x-y||](https://tex.z-dn.net/?f=%7C%7Cx%2By%7C%7C%3D%7C%7Cx-y%7C%7C)
Square also would be equal
![||x+y||^2=||x-y||^2\\||x||^2+||y||^2+2x,t=||x||^2+||y||^2-2x.y\\x.y =0](https://tex.z-dn.net/?f=%7C%7Cx%2By%7C%7C%5E2%3D%7C%7Cx-y%7C%7C%5E2%5C%5C%7C%7Cx%7C%7C%5E2%2B%7C%7Cy%7C%7C%5E2%2B2x%2Ct%3D%7C%7Cx%7C%7C%5E2%2B%7C%7Cy%7C%7C%5E2-2x.y%5C%5Cx.y%20%3D0)
Hence inner product of x and y is 0