Answer:
all possible y values
Step-by-step explanation:
5y + 2 is defined for all values of y.
To solve for x, you need to isolate/get the variable "x" by itself in the equation:
3x - 3(x + 1) = 3 Distribute/multiply -3 into (x + 1)
3x + (-3)x + (-3)1 = 3
3x - 3x + 1 = 3
1 = 3
Your answer is no solution because the variable "x" is canceled out and 1 ≠ 3
Answer:
p^2 + q^2 = 22/9.
Step-by-step explanation:
For a quadratic function ax^2 + bx + c if the zeroes are A and B then
A + B = -b/a and AB = c/a.
2x^2 - 7x + 3
Now p and q are the zeroes of the above function so
p + q = 7/3 and pq = 3/2.
Now p^2 + q^2 = (p + q)^2 - 2pq
= (7/3)^2 - 2* 3/2
= 49/9 - 3
= 49/4 - 27/9
= 22/9.
Answer:
(-3, 3)
Step-by-step explanation:
You need to find the median of the x value, and then the median of the y value, and that's your point. Good luck. I never liked graphing.