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3 years ago

13

Write a real word problem that can be modeled by 4 x (-7)

1 answer:

MrMuchimi3 years ago

5 0

Answer:

The bakery also has 4 cakes, and Yena wants to get 7 times the cake from the bakery. How much will all of Yena take?

Step-by-step explanation:

You might be interested in

How to factor 4x^2+7x-15

GuDViN [60]

$4x^2+7x-15$

Break the expression into group:

$(4x^2+5x)+(12x-15)$

factor out x from 4x² - 5x : x (4x-5)
factor out 3 from 12x-15 : 3 (4x-5)

$=x(4x-5)+3(4x-5)$

factor out common term (4x-5) :

$= (4x-5)(x+3)$

hope this helps!

4 0

3 years ago

A company is made up of 3000 employees but plans on increasing its staff by 12 percent. How many employees will work at this com

Alecsey [184]

I need to make it 20 characters long

4 0

3 years ago

¿Cuál es la probabilidad de que al lanzar un dado se obtenga un número impar y menor que 5?

NemiM [27]

Answer:

4/6 or 66.67 percent

Step-by-step explanation:

5 0

2 years ago

Marcus wants to determine how age and weight are related to exercise preference in his town. He selects a simple random sample o

mario62 [17]

Answer:

He will be unable to tell whether a difference in exercise preference is related to a difference in age or to a difference in weight

Step-by-step explanation:

age could be a factor to exercise as well as weight so both affect the outcome so he has two samples

3 0

3 years ago

A piece of cardboard has the dimensions (x + 15) inches by (x) inches with the area of 60 in 2 . Write the quadratic equation th

pochemuha

Answer:

$x^2 + 15x - 60 = 0$

The actual dimension is 18.28 by 3.28

Step-by-step explanation:

Given

Dimension:

$(x + 15)\ by\ x$

$Area = 60in^2$

Required

Determine the quadratic equation and get the possible values of x

Solving (a): Quadratic Equation.

The cardboard is rectangular in shape.

Hence, Area is calculated as thus:

$Area = Length * Width$

$60= (x + 15) * x$

Open Bracket

$60= x^2 + 15x$

Subtract 60 from both sides

$x^2 + 15x - 60 = 0$

<em>Hence, the above represents the quadratic equation</em>

Solving (b): The actual dimension

First, we need to solve for x

This can be solved using quadratic formula:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

Where

$a = 1$

$b = 15$

$c = -60$

So:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

$x = \frac{-15 \± \sqrt{15^2 - 4*1*-60}}{2*1}$

$x = \frac{-15 \± \sqrt{225 + 240}}{2}$

$x = \frac{-15 \± \sqrt{465}}{2}$

$x = \frac{-15 \± \21.56}{2}$

Split:

$x = \frac{-15 + 21.56}{2}$ or $x = \frac{-15 - 21.56}{2}$

$x = \frac{6.56}{2}$ or $x = \frac{-36.36}{2}$

$x = 3.28$ or $x = -18.18$

But length can't be negative;

So:

$x = 3.28$

The actual dimensions: $(x + 15)\ by\ x$ is

$Length =3.28 +15$

$Length =18.28$

$Width = x$

$Width =3.28$

<em>The actual dimension is 18.28 by 3.28</em>

3 0

3 years ago