The probability of picking a ticket that is green or has a number greater than four is 3/5
<h3>How to determine the probability?</h3>
The given parameters are:
Yellow = 1 - 5
Green = 1 - 5
Total = 10
There are 2 cards whose numbers are greater than 4 i.e. Yellow 5 and Green 5
So, we have:
P(Number greater than 4) = 2/10
There are 5 green cards.
So, we have:
P(Green) = 5/10
Also, 1 green card is numbered greater than 4
So, we have:
P(Green greater than 4) = 1/10
The required probability is:
P = P(Green) + P(Number greater than 4) - P(Green greater than 4)
This gives
P = 5/10 + 2/10 - 1/10
Evaluate
P = 6/10
Simplify
P =3/5
Hence, the probability of picking a ticket that is green or has a number greater than four is 3/5
Read more about probability at:
brainly.com/question/11234923
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The point-slope form:
We have the points (3, 6) and (-2, 1). Substitute:
<h3>Answer: 4. y - 6 = 1(x - 3)</h3>
Y = 3x. the y axis goes up by an interval of 3.
Answer: $25 spent
Step-by-step explanation: the boy spent $15/total.
15/total=3/8
Divide by common factor: $15/3=$5 (1/8 total money
$5x8=$40
$40-$15=$25 spent
Answer:
a) r₁₂ = 104.36
In general, rₙ = arⁿ⁻¹
b)
- rabbit food consumed during the 10th year is approximately 832 pounds
- rabbit food consumed in total for the 1st through 10th years is approximately 5265 pounds
Step-by-step explanation:
Given that:
r1 = 30 and a farm grows by 12%
a = 30 and the common ratio r = 1.12
now
n r
1 30.00
2 33.60
3 37.63
4 42.15
5 47.21
6 52.87
7 59.21
8 66.32
9 74.28
10 83.19
11 93.18
12 104.36
Therefore r₁₂ = 104.36
In general, rₙ = arⁿ⁻¹
b)
if each rabbit consume 10 lbs of rabbit food each year
n r food consumed(lbs)
1 30.00 300
2 33.60 336
3 37.63 376
4 42.15 422
5 47.21 472
6 52.87 529
7 59.21 592
8 66.32 663
9 74.28 743
10 83.19 832
total 5265
Therefore, the rabbit food consumed during the 10th year is approximately 832 pounds
And the rabbit food consumed in total for the 1st through 10th years is approximately 5265 pounds
