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alex41 [277]
3 years ago
6

I need help finding the answer

Mathematics
1 answer:
mezya [45]3 years ago
7 0
Bkou'e jusiter bove;re 20 kigtser 1 pofbst 
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4 years ago
A town is planning a playground. It wants to fence in a rectangular space using an existing wall. What is the greatest area it c
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Answer:

1250 ft^{2}

Step-by-step explanation:

We are given that the playground is fenced on three sides of the playground and the four side has an existing wall.

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As the fencing is done using 100 feet of fence. We get the relation between the sides and the fence as, X + 2Y = 100.

As, X + 2Y = 100 → X = 100 - 2Y

Now, the area of the rectangle = XY = X × ( 100 - 2Y ).

i.e Area of the rectangle = -2Y^{2} +100Y.

The general form of a quadratic equation is y=ax^{2}+bx+c.

The maximum value of a quadratic equation is given by x=\frac{-b}{2a}.

Therefore, the greatest value of -2Y^{2} +100Y is at Y = \frac{-100}{2 \times -2} = \frac{-100}{-4} = 25.

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Hence, the area of the rectangle is XY = 50 × 25 = 1250 ft^{2}.

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