Using a calculator with the binompdf and binomcdf features, I can calculate these values. My calculator is a TI-83 plus, and the features are found under the 2nd, Vars keys (Scroll up or down until you see them).
If "exactly" is to be found, use binompdf:
binompdf(number of trials, probability of success, exactly number)
ANSWER for exactly 3: binompdf(8, 0.5, 3) = 0.21875 = 21.875%
If "at least" is to be found, use binomcdf:
binomcdf(number of trials, probability of success, at least number - 1)
ANSWER for at least 6: binomcdf(8, 1/2, 5) ≈ 0.8555 ≈ 85.55%
If "at most" is to be found, use binomcdf:
binomcdf(number of trials, probability of success, at most number)
ANSWER for at most 3: binomcdf(8, 0.5, 3) ≈ 0.3633 ≈ 36.33%
Answer:
Yes, x=1 is the solution
Step-by-step explanation:
You would divide both sides of the equation by 2, that leaves you with x+13=14
Next you would move your constant, which in this case is 13, so x=14-13
Then you would subtract the numbers by each other so 14-13 equals one which makes x=1
Answer:
option A, option C, option D
Step-by-step explanation:
a) 1 ÷ m/6
can be written as
÷ 
b) sides in (m/6) will change if both has to multiply
c) 1 ÷ m/6
can be written as
1 * 6/m
1(
) and wont make change to answer. so matches with the question.
d)
1 ÷ m/6
1 * 6/m
1 * 6 * 
6 *
6 ÷ m ..therefore true
e)
1 ÷ m/6
1 * 6/m
6/m ....does not match or can be converted to the following so wrong
- Therefore A, C, D are correct and B and E is wrong.
Answer:
no its x = - 4
Step-by-step explanation:
-1 cause 13- 12= negative 1
