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3 years ago

Which statement describes the solutions of the equation? 4x/3x+1 = x/2x+10

Mathematics

2 answers:

Reptile [31]3 years ago

6 0

Answer:

C. The equation has two valid solutions and no extraneous solutions.

Explanation:

In photo below

I hope this helps

stiks02 [169]3 years ago

4 0

Answer:

<h3> The equation has one valid solution and no extraneous of solutions.</h3>

Step-by-step explanation:

Given the expression;

4x/3x+1 = x/2x+10

We are to get the nature of the value of x

Cross multiply;

x(3x+1) = 4x(2x+10)

3x²+x = 8x²+40x

Collect like terms;

3x²-8x² + x - 40x = 0

-5x²+x -40x = 0

-5x²-39x = 0

-5x² = 39x

-5x = 39

x = -39/5

<em>Since we have just one value of x hence, the equation has one valid solution and no extraneous of solutions.</em>

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kakasveta [241]

Answer:

in step 4

Step-by-step explanation:

we have

$0.5(-12c+6)-3(c+4)+10(c-5)\\\\step1=-12c(0.5)+6(0.5)-3(c+4)+10(c-5)\\\\=-6c+3-3(c+4)+10(c-5)\\\\$

so step 1 is correct

step 2

$-6c+3-3(c+4)+10(c-5)\\\\=-6c+3+c(-3)+4(-3)+10(c-5)\\\\=-6c+3-3c-12+10(c-5)$

so step 2 is correct

step 3

$-6c+3-3c-12+10(c-5)\\\\=-6c+3-3c-12+c(10)-5(10)\\\\=-6c+3-3c-12+10c-50$

so step 3 is correct

step 4

$-6c+3-3c-12+10c-50\\\\=(-6c-3c+10c)+(3-12-50)\\\\=(-6-3+10)c+(-9-50)\\\\=(-9+10)c-59\\\\=c-59$

so step 4 is incorrect

5 0

3 years ago

What is (2-7x)+34-6-(758+8)

pickupchik [31]

Step-by-step explanation:

2- 7x + 34 - 6-(766)

2-7x + 34 - 6 - 766

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-7x - 736

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3 years ago

While walking between gates at an airport, you notice a child running along a moving walkway. Estimating that the child runs at

tekilochka [14]

The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

<h3>How to estimate the speed of the moving walkway relative to the airport terminal?</h3>

Let x be the speed of the walkway.

(2.8 + x) = speed of child moving in direction of the walkway

(2.8 - x) = speed of child moving against the direction of the walkway

Travel time = distance/speed

Travel time of child moving in direction of walkway = 23/(2.8+x)

Total elapsed time given = 29s

23/(2.8 + x)+ 23 / (2.8-x) = 29

LCD = (2.8 + x)(2.8 - x)

$23(2.8 - x) + 23(2.8 + x) = 29(2.8 + x)(2.8 -x)$

simplifying the equation, we get

$23*2.8-23x+23*2.8+23x=29(2.8^2-x^2)$

$23(2.8+2.8)/29=2.8^2-x^2$

$x^2=(2.8)^2-(23*5.6)/29)=3.4$

$x=\sqrt{3.4}=1.84m/s$

Speed of walkway = 1.84 m/s

The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

To learn more about Speed refer to:

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Answer:

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Step-by-step explanation:

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