Answer:
Evaporation
Explanation:
Though it doesn't require high temperatures to do so
<u>Answer:</u> The final volume will be 71.8 L
<u>Explanation:</u>
To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
where,
are the initial volume and temperature of the gas.
are the final volume and temperature of the gas.
We are given:
Putting values in above equation, we get:
Hence, the final volume will be 71.8 L
The volume of HCOOH is 0.003 Lt and the volume of HCOONa is 0.017 LT.
Explanation:
For acidic buffer
PH = Pka + log
4.25 = 3.75 + log
log = 0.75
log = 5.62 is considered as equation 1.
Let V₁ ml of HCOOH and V₂ml of HCOONA was mixed and the final volume is 100 ml .
V₁ *0.5 + V₂ *0.5 =0.1 * 100
V₁+V₂ = = 20 is the second equation.
Now concentration of salt and acid are
V₂ [salt] = 0.5/100 and v₁ [acid] = 0.5/100
by substituting these in equation 1 we get,
= 5.62
V₂ = V₁ * 5.62 is the 3 rd equation
by solving 2 and 3 we get,
5.62 V₁ + V₁ = 20
= 6.62 V₁ = 20
V₁ = 3.02 ml
V₁ = 0.003 LT
V₂ = V₁ * 5.62
V₂ = 0.017 LT
Hence the volume of HCOOH is 0.003 Lt and the volume of HCOONa is 0.017 LT.
The reaction for the formation of MgO(s):
2 Mg (s) + O2(g) -à
2MgO(s) ΔH = -601.24
kJ/mol
<span>The enthalpy
information is taken from: http://webbook.nist.gov/cgi/inchi?ID=C1309484&Mask=2</span>
From the equation and with an enthalpy change of -231 kJ:
-231 kJ * 2 mol Mg * (1/-601.24 kJ/mol) = 0.76841 mol Mg
Then, with the molar mass of MgO = 40.3,
0.76841 mol Mg *(2 mol MgO/2 mol Mg)* 40.3 g/mol MgO = <span>30.967 g MgO</span>
First, you need to know the molar mass of the compound. The compound Aluminum Sulfate has a molar mass of 342.15 g/mol. From the subscript of the compound, there are 4*3 = 12 moles of oxygen in 1 mole of the compound. The solution is as follows:
6.90 g Al₂(SO₄)₃*(1 mol/342.15 g)*(12 mol O/1 mol Al₂(SO₄)₃)*(6.022×10²³ atoms/mole) = 1.457×10²³ atoms of oxgyen