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JulijaS [17]
3 years ago
7

10. Liquid changing to gas only at the surface is called

Chemistry
1 answer:
mina [271]3 years ago
3 0

Answer:

Evaporation

Explanation:

Though it doesn't require high temperatures to do so

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Interpolate: Use the equation to determine what the student enrollment in 2003 likely was.
sdas [7]

Answer:

1244 students

Explanation:

That would be y = 82*3 + 998

= 1244.

5 0
3 years ago
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Which is the largest thing in the world???????????
Ksivusya [100]

<em>S</em><u><em>equoia trees</em></u> are the largest thing in the world or planet

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5 0
3 years ago
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What is the acceleration object velocity of +25m/s to rest in 5.0 s
Irina-Kira [14]

The average acceleration is -5.0 m·s⁻².

The formula for acceleration (<em>a</em>) is

a = \frac{v_{f}- v_{i}}{t}

v_{f} = 25 m·s⁻¹;  v_{i} = 0; t = 5.0 s

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The negative sign tells you that the object is <em>slowing down</em>, i.e., it is <em>decelerating</em>.


4 0
3 years ago
The concentrations of the products at equilibrium are [pcl3] = 0.180 m and [cl2] = 0.250 m. what is the concentration of the rea
sineoko [7]
We have Kc = 4.2 x 10^-2 (given but missing in the question)
and When the balanced equation for this reaction is:
PCl5(g) ↔ PCl3(g) + Cl2(g)
so, according to the Kc formula:
Kc = the concentration of products / the concentration of the reactants
so, to get the concentration of the reactants in equilibrium, the concentration of the products / the concentration of the reactants should equal the Kc value which is given in the question (missing in your question).
So by substitution in Kc formula: 
Kc   = [PCl3]*[Cl2] / [PCl5]
4.2 x 10^-2 =  0.18 * 0.25 /[PCl5]
∴[PCl5] = 0.18*0.25 / 4.2x10^-2 = 1.07
So the concentration of the reactants in equilibrim = 1.07

4 0
3 years ago
Determine a detailed mechanism for the chlorination of benzene using cl2 and fecl3.
RUDIKE [14]
Step (1):
Generation of electrophile: by the action of Lewis acid FeCl₃ on Cl₂ to serve as a source of Cl⁺ (Electrophile)
Step (2):
Addition of electrophile to form carbocation:
addition of electrophile to form C-Cl bond and form carbocation which is stabilized by resonance.
Step (3):
Loss of proton to re-form the aromatic ring by the action of FeCl₄⁻ which removes proton from carbon containing Cl and forming the aromatic ring again

8 0
3 years ago
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