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3 years ago

Simplify: Write your answer in scientific notation. (3.3 x 10^7) + (7.7 x 10^8)

Mathematics

1 answer:

maks197457 [2]3 years ago

6 0

The answer is 8.03x10^8

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Can someone answer this? Thanks :)

Maslowich

Answer:

15ft

Step-by-step explanation:

Draw out the picture and use the Pythagorean theorem (equation is written in blue) to solve.

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3 years ago

Determine the next step for solving the quadratic equation by completing the square.

Studentka2010 [4]

Answer:

The solutions are $x=\frac{1+\sqrt{7}}{2}$ and $x=\frac{1-\sqrt{7}}{2}$

Step-by-step explanation:

we have

$0=-2x^{2}+2x+3$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$-3=-2x^{2}+2x$

Factor the leading coefficient

$-3=-2(x^{2}-x)$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$-3-0.5=-2(x^{2}-x+0.5^{2})$

$-3.5=-2(x^{2}-x+0.5^{2})$

Rewrite as perfect squares

$-3.5=-2(x-0.5)^{2}$

$7/4=(x-0.5)^{2}$

square root both sides

$x-0.5=(+/-)\sqrt{\frac{7}{4}}$

$x-\frac{1}{2}=(+/-)\frac{\sqrt{7}}{2}$

$x=\frac{1}{2}(+/-)\frac{\sqrt{7}}{2}$

$x=\frac{1+\sqrt{7}}{2}$

$x=\frac{1-\sqrt{7}}{2}$

4 0

3 years ago

Find the median of these numbers ? 2,7,5,4,3

kotykmax [81]

Answer:

Step-by-step explanation:

MARK AS BRAINLIST!!

5 0

3 years ago

Read 2 more answers

Digital Literacy Semi Activity 5.1.1 - Telecommunications Review1. Match the parts of software applications with what they do:Al

Ilya [14]

1-g

2-f

3-a

5-g

6-h

7-b

8-a

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1 year ago

The heights of women aged 20 to 29 are approximately normal with mean 64 inches and standard deviation 2.7 inches. men the same

Artyom0805 [142]

<span>To find the z-scores, find the difference in the number of inches for each value from the mean and then divide that by the standard deviation. For women at 72 inches (6'), this would be (72-64) / 2.7, or a z-score of +2.963. For a male at 72 inches, this would be (72-69.3)/2.8, or +0.964. This shows that the woman at 6 feet tall is more rare in the distribution than a man at 6 feet tall.</span>

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3 years ago