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weqwewe [10]
3 years ago
9

Chose one value for x and substitute the value in the equation to get your answer pick x=15 or x=12 or x=10 2x+13

Mathematics
2 answers:
lora16 [44]3 years ago
8 0
If I pick 10, then 2(10)+13=33
If I pick 15, then 2(15)+13=43
If I pick 12, then 2(12)+13=37
11111nata11111 [884]3 years ago
7 0

Step-by-step explanation:

If I pick x = 15 , 2x+13=2(15)+13=30+13=43

If I pick x =12 , 2x+13=2(12)+13=24+13=37

If I pick x =10. , 2x+13=2(10)+13=20+13=33

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In x² , what is the 2 called?
alexandr402 [8]

Answer:

<h2>an exponent</h2>

Step-by-step explanation:

In x², here the 2 is exponent while x is base.

7 0
3 years ago
Read 2 more answers
5. Solve the equation z^2 + 4z - 9 = 0 by completing the square.
Luba_88 [7]

Answer:

A. Z = 2 + N13

Step-by-step explanation:

Let's solve your equation step-by-step.

0=z2+4z−9

Step 1: Subtract z^2+4z-9 from both sides.

0−(z2+4z−9)=z2+4z−9−(z2+4z−9)

−z2−4z+9=0

For this equation: a=-1, b=-4, c=9

−1z2+−4z+9=0

Step 2: Use quadratic formula with a=-1, b=-4, c=9.

z=

−b±√b2−4ac

2a

z=

−(−4)±√(−4)2−4(−1)(9)

2(−1)

z=

4±√52

−2

z=−2−√13 or z=−2+√13

8 0
3 years ago
Solve v+8&lt;3 or -8v-40 .
Setler79 [48]
The answer is:

v < -5 or v > 5

Hope this helps ✨❤️
6 0
2 years ago
Rectangle R has varying length l and width w but a constant perimeter of 4 ft. A. Express the area A as a function of l. What do
ivanzaharov [21]
Given:
l = length of the rectangle
w = width of the rectangle
P = 4 ft, constant perimeter

Because the given perimeter is constant,
2(w + l) = 4
w + l = 2
w = 2 - l            (1)

Part A.
The area is
A = w*l 
   = (2 - l)*l
 A  = 2l - l²
This is a quadratic function or a parabola.

Part B.
Write the parabola in standard form.
A = -[l² - 2l]
   = -[ (l -1)² - 1]
   = -(l -1)² + 1
This is a parabola with vertex at (1, 1). Because the leading coefficient is negative the curve is downward, as shown below.

The maximum value occurs at the vertex, so the maximum value of A = 1.
From equation (1), obtain
w = 2 - l = 2 - 1 = 1.
The maximum value of the area occurs when w=1 and l=1 (a square).

Answer:
The area is maximum when l=1 and w=1.
The geometric argument is based on the vertex of the parabola denoting maximum area.

4 0
3 years ago
I'll give brainliest ​
Tpy6a [65]

Given:

\angle a and \angle b are complementary angles.

\angle a=32^\circ

To find:

The measure of \angle b.

Solution:

According to the definition of the complimentary angles, the sum of two complementary angles is always 90 degree.

It is given that, \angle a and \angle b are complementary angles. So,

\angle a+\angle b=90^\circ

32^\circ+\angle b=90^\circ

\angle b=90^\circ-32^\circ

\angle b=58^\circ

Therefore, the measure of \angle b is 58°.

3 0
3 years ago
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