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AysviL [449]
2 years ago
7

You are adding more features to a linear regression model and hope they will improve your model. If you add an important feature

, the model may result in.
1. Increase in R-square
2. Decrease in R-square
A) Only 1 is correct
B) Only 2 is correct
C) Either 1 or 2
D) None of these
Computers and Technology
1 answer:
Ludmilka [50]2 years ago
8 0

Answer:

The answer is "Option A".

Explanation:

Add extra functionality, otherwise, it increases the R-square value, which is defined in the following points:      

  • To incorporate essential elements, R-square is explicitly promoted.
  • It Increases the R-square value, which is an additional feature.
  • It removes the features, which provide the value of the reduce R-square.
  • After incorporating the additional features is used as the model, which is R-square, which is never reduced.
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You are given a string of n characters s[1 : : : n], which you believe to be a corrupted text document in which all punctuation
alexdok [17]

Answer: provided in the explanation section

Explanation:

Given that:

Assume D(k) =║ true it is [1 : : : k] is valid sequence  words or false otherwise

  • To determine D(n)

now the sub problem s[1 : : : k] is a valid sequence of words IFF s[1 : : : 1] is a valid sequence of words and s[ 1 + 1 : : : k] is valid word.

So, from here we have that D(k) is given by the following recorance relation:

D(k) = ║ false maximum (d[l]∧DICT(s[1 + 1 : : : k]) otherwise

Algorithm:

Valid sentence (s,k)

D [1 : : : k]             ∦ array of boolean variable.

for a ← 1 to m

do ;

d(0) ← false

for b ← 0 to a - j

for b ← 0 to a - j

do;

if D[b] ∧ DICT s([b + 1 : : : a])

d (a) ← True

(b). Algorithm Output

      if D[k] = = True

stack = temp stack           ∦stack is used to print the strings in order

c = k

while C > 0

stack push (s [w(c)] : : : C] // w(p) is the position in s[1 : : : k] of the valid world at // position c

P = W (p) - 1

output stack

= 0 =

cheers i hope this helps !!!

8 0
3 years ago
Which command compiles the Java source code file Welcome.java?
GarryVolchara [31]

Answer:

javac Welcome.java

Explanation:

In order to the file to compile with the default compiler in the JDK, the instruction must be of the form:

javac filename

(Note: the filename with the .java extension)

3 0
3 years ago
How does the occupational outlook affect the monetary benefits of a career
Ksivusya [100]
If there are changes to the responsibilities in a career, the typical outcome will change.
4 0
3 years ago
Write a police description a person who know you well​
SIZIF [17.4K]

Answer:

I will be describing Jude. He is a neighbor.

Explanation:

A police description refers to the method of describing a person using high-level detailing. An example is given below:

  1. He is a Five feet-three male caucasian
  2. With brown eyes and
  3. an Australian accent
  4. He has a military haircut
  5. About 38 years
  6. Weighs about 95Kg
  7. and dresses casually
  8. he walks with a slant to the left
  9. a dove tattoed at the back of his neck
  10. and a birthmark on his left ear lobe

Cheers

3 0
3 years ago
You are a visitor at a political convention with delegates; each delegate is a member of exactly one political party. It is impo
Fed [463]

Answer:

The algorithm is as follows:

Step 1: Start

Step 2: Parties = [All delegates in the party]

Step 3: Lent = Count(Parties)

Step 4: Individual = 0

Step 5: Index = 1

Step 6: For I in Lent:

Step 6.1: If Parties[Individual] == Parties[I]:

Step 6.1.1: Index = Index + 1

Step 6.2: Else:

Step 6.2.1 If Index == 0:

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

Step 7: Else

Step 7.1: Index = Index - 1

Step 8: Print(Party[Individual])

Step 9: Stop

Explanation:

The algorithm begins here

Step 1: Start

This gets the political parties as a list

Step 2: Parties = [All delegates in the party]

This counts the number of delegates i.e. the length of the list

Step 3: Lent = Count(Parties)

This initializes the first individual you come in contact with, to delegate 0 [list index begins from 0]

Step 4: Individual = 0

The next person on the list is set to index 1

Step 5: Index = 1

This begins an iteration

Step 6: For I in Lent:

If Parties[Individual] greets, shakes or smile to Party[i]

Step 6.1: If Parties[Individual] == Parties[I]:

Then they belong to the same party. Increment count by 1

Step 6.1.1: Index = Index + 1

If otherwise

Step 6.2: Else:

This checks if the first person is still in check

Step 6.2.1 If Index == 0:

If yes, the iteration is shifted up

Step 6.2.2: Individual = I

Step 6.2.3: Index = 1

If the first person is not being checked

Step 7: Else

The index is reduced by 1

Step 7.1: Index = Index - 1

This prints the highest occurrence party

Step 8: Print(Party[Individual])

This ends the algorithm

Step 9: Stop

The algorithm, implemented in Python is added as an attachment

<em>Because there is an iteration which performs repetitive operation, the algorithm running time is: O(n) </em>

Download txt
5 0
2 years ago
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