2 years ago

Can someone help me please?

Mathematics

1 answer:

alekssr [168]2 years ago

3 0

Answer:

SHEEESH

Step-by-step explanation:

sneaker meetup see who we boutta finesse

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Answer:

$a_{n+1}=0.2a_n$ for all n>0, $a_1=16$

Step-by-step explanation:

Let $\{a_n\}=\{16,3.2,0.64,0.128,\cdots \}$ be the sequence described.

A geometric sequence has the following property: there exists some r (the ratio of the sequence) such that $\frac{a_{n+1}}{a_n}=r$ forr all n>0.

To find r, note that

$\frac{3.2}{16}=\frac{32}{10(16)}=\frac{2}{10}=\frac{1}{5}=0.2$

Similarly

$\frac{0.64}{3.2}=\frac{64}{10(32)}=\frac{1}{5}=0.2$

$\frac{0.128}{0.64}=\frac{1}{5}=0.2$

Thus $a_{n+1}=r a_n=\frac{a_n}{5}=0.2a_n$ for all n>0, and $a_1=16$

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