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3 years ago

10

-3(-5x-2u+1) use the distributive property to remove the parentheses

1 answer:

il63 [147K]3 years ago

3 0

Answer:

15x+6u−3

Step-by-step explanation:

This means -3 times -5x, -3 times -2u, and -3 times 1.

Do this and you have, 15x+6u-3.

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Can someone help me with this geometry question?

lana66690 [7]

Answer:

whats the question

Step-by-step explanation:

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3 years ago

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What is the distance between the 2 points? (Use Pythagorean Theorem)

JulsSmile [24]

4^2+3^2 = DISTANCE^2

16+9 = DISTANCE^2

25 = DISTANCE^2 | sqrt

5 = DISTANCE

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3 years ago

Finding Hypotenuse Lengths. Find the length of the hypotenuse.

ioda

Answer:

11) $\frac{3\sqrt{5}}{2}$

12) $4\sqrt{5}$

13) $22$

14) $18$

15) $2$

16) $24\sqrt{3}$

Step-by-step explanation:

For these problems I used the pythagorean theorem: $a^{2}+ b^{2}= c^{2}$ and SOHCAHTOA

Sin = $\frac{opposite}{hypotenuse}$

Cos = $\frac{adjacent}{hypotenuse}$

Tan = $\frac{opposite}{hypotenuse}$

11)

First find the length of the bottom side by using Cos

$cos(60)=\frac{x}{3}$

$3(cos(60))=x$

$1.5=x$

Then plug it into the formula for the pythagorean theorem to find the hypotenuse

$3^{2}+ 1.5^{2}= c^{2}$

$9+2.25=c^{2}$

$\sqrt{11.25}=\sqrt{c^{2}}$

$\frac{3\sqrt{5}}{2}$

12)

Find the length of the bottom side using Cos

$cos(60)=\frac{x}{8}$

$8(cos(60))=x$

$4=x$

Then plug it into the formula for the pythagorean theorem to find the hypotenuse

$8^{2}+ 4^{2}= c^{2}$

$64+16=c^{2}$

$\sqrt{80} =\sqrt{c^{2} }$

$4\sqrt{5}$

13)

Find the length of the other side by using Tan

$tan(30)=\frac{x}{11\sqrt{3} }$

$11\sqrt{3}* (tan(30)=x$

$11=x$

Then plug it into the formula for the pythagorean theorem to find the hypotenuse

$(11\sqrt{3}) ^{2}+ 11^{2}= c^{2}$

$363+121=c^{2}$

$\sqrt{484} =\sqrt{c^{2}}$

$22$

14)

(This is probably an easier way to do these problems)

Find the hypotenuse by using Cos ( $\frac{adjacent}{hypotenuse}$ )

$cos(60)=\frac{9}{x}$

$cos(60)x=9$

$x=\frac{9}{cos(60)}$

$x=18$

15)

Find the hypotenuse using Sin ( $\frac{opposite}{hypotenuse}$ )

$sin(30)=\frac{1}{x}$

$sin(30)x=1\\x=\frac{1}{sin(x)}$

$x=2$

16)

Find the hypotenuse using Cos ( $\frac{adjacent}{hypotenuse}$ )

$cos(60)=\frac{12\sqrt{3} }{x}$

$cos(60)x=12\sqrt{3}$

$x=\frac{12\sqrt{3} }{cos(60)}$

$x=24\sqrt{3}$

5 0

4 years ago

WILL GIVE BRAINLIEST<br> Write the product using exponents. (−9)⋅(−9)⋅(−9)⋅(−9)⋅(−9)

Daniel [21]

Answer:

-9^5

Step-by-step explanation:

(-9)*(-9)*... is -9^5

Please mark as Brainliest! :)

Have a nice day.

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3 years ago

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borishaifa [10]

O The line increases from the left to right

O The line crosses the x-axis at 2.5

O The line does not enter quadrant II at all...

...Are your answers

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3 years ago