-25-6= -25 + -6 = -31

Suppose that the growth rate of children looks like a straight line if the height of a child is observed at the ages of 24 mont

lana [24]

Answer:

The supposition is incorrect.

Step-by-step explanation:

The growth rate of a child is not constant, so height versus time does not look like a straight line. Nothing is wrong with the prediction made using the false assumption. You can conclude anything you like when you start with a false premise.

5 0

3 years ago

What is is 2,704 4 is the underline digit

GrogVix [38]

Which one is underline digit

3 0

3 years ago

PLEASE HELP!!!!

Bogdan [553]

Answer:

Step-by-step explanation:

We would apply the formula for binomial distribution which is expressed as

P(x = r) = nCr × p^r × q^(n - r)

Where

x represent the number of successes.

p represents the probability of success.

q = (1 - r) represents the probability of failure.

n represents the number of trials or sample.

From the information given,

p = 18% = 18/100 = 0.18

q = 1 - p = 1 - 0.18

q = 0.82

n = 5

Therefore,

P(x ≤ 2) = p(x = 0) + p(x = 1) + p(x = 2)

P(x = 0) = 5C0 × 0.18^0 × 0.82^(5 - 0)

P(x = 0) = 0.37

P(x = 1) = 5C1 × 0.18^1 × 0.82^(5 - 1)

P(x = 1) = 0.41

P(x = 2) = 5C2 × 0.18^2 × 0.82^(5 - 2)

P(x = 2) = 0.18

Therefore,

P(x ≤ 2) = 0.37 + 0.41 + 0.18 = 0.96

5 0

2 years ago

A random sample of n = 40 observations from a quantitative population produced a mean x = 2.2 and a standard deviation s = 0.29.

zmey [24]

Answer:

$t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18$

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.18)=0.0177$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

Step-by-step explanation:

Data given and notation

$\bar X=2.2$ represent the sample mean

$s=0.29$ represent the sample standard deviation

$n=40$ sample size

$\mu_o =2.1$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 2,1, the system of hypothesis would be:

Null hypothesis: $\mu \leq 2.1$

Alternative hypothesis: $\mu > 2.1$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.18)=0.0177$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

7 0

3 years ago

How do you convert a division word problem into a fraction?

baherus [9]

For example: if the word problem were simply "4 divided by 2", the fraction would be a 4 with a line underneath and the 2 underneath that.

I hope I made this possible to understand... let me know if you were referring to something else!

4 0

3 years ago

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