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3 years ago

14

Arthur's dog, Shep, had to go on a diet. After three months of dieting, Shep had lost 16% of his weight, which was 24 pounds. Ho

w much did Shep weigh before he was put on a diet?

1 answer:

lidiya [134]3 years ago

5 0

Answer: 150 pounds

Step-by-step explanation:

Let her initial weight be represented by x.

Since Shep had lost 16% of his weight, which was 24 pounds. Shep weight before he was put on a diet would be:

16% × x = 24

0.16 × x = 24

0.16x = 24

x = 24/0.16

x = 150 pounds

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A privately owned lake contains two types of game fish, bass and trout. The owner provides two types of food, A and B, for these

Vinvika [58]

Answer:

133 fishes

Step-by-step explanation:

Units of food A = 400 units

Units of food B = 400 units

Fish Bass required 2 units of A and 4 units of B.

Fish Trout requires 5 units of A and 2 units of B.

i. For food A,

total units of food A required = 2 + 5

= 7 units

number of bass and trout that would consume food A = 2 x $\frac{400}{7}$

= 114.3

number of bass and trout that would consume food A = 114

ii. For food B,

total units of food B required = 4 + 2

= 6 units

number of bass and trout that would consume food B = 2 x $\frac{400}{6}$

= 133.3

number of bass and trout that would consume food B = 133

Thus, the maximum number of fish that the lake can support is 133.

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seropon [69]

Answer:

8-1

Step-by-step explanation:

I know things : )

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3 years ago

Read 2 more answers

The isosceles trapezoids, ABCD and EFGH, are similar quadrilaterals. The scale factor between the trapezoids is 2:3, = 6 centime

Bingel [31]

Answer:

Part A) see the explanation

Part B) see the explanation

Part C) The perimeter of trapezoid ABCD is 32 centimeters and the perimeter of trapezoid EFGH is 48 centimeters

Step-by-step explanation:

<u><em>The complete question is</em></u>

The isosceles trapezoids, ABCD and EFGH, are similar quadrilaterals. The scale factor between the trapezoids is 2:3, GH = 6 centimeters, AD = 8 centimeters, and AB is three times the length of DC

Part A) Write a similarity statement for each of the four pair of corresponding sides

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional

The corresponding sides are

AB and EF

BC and FG

CD and GH

AD and EH

so

$\frac{AB}{EF}=\frac{BC}{FG}=\frac{CD}{GH}=\frac{AD}{EH}$

Part B) Write a congruence statement for each of the four pair of corresponding angles.

we know that

If two figures are similar, then its corresponding angles are congruent

The corresponding angles are

∠A and ∠E

∠B and ∠F

∠C and ∠G

∠D and ∠H

so

∠A ≅ ∠E

∠B ≅ ∠F

∠C ≅ ∠G

∠D ≅ ∠H

Part C) Determine the perimeter for each of the isosceles trapezoids

we have

The scale factor between the trapezoids is 2:3, GH = 6 centimeters, AD = 8 centimeters, and AB is three times the length of DC

step 1

Find the measure of CD

Remember that

The ratio between corresponding sides is proportional and this ratio is the scale factor

Let

z ----> the scale factor

$z=\frac{2}{3}$

so

$\frac{2}{3}=\frac{CD}{GH}}$

we have

$GH=6\ cm$

substitute

$\frac{2}{3}=\frac{CD}{6}}\\\\CD=4\ cm$

step 2

Find the measure of AB

Remember that

AB is three times the length of DC

so

$AB=3DC$

$DC=CD=4\ cm$

substitute

$AB=3(4)=12\ cm$

step 3

Find the measure of BC

Remember that in an isosceles trapezoid, the legs are equal

so

BC=AD

we have

$AD=8\ cm$

therefore

$BC=8\ cm$

step 4

Find the perimeter of trapezoid ABCD

$P=AB+BC+CD+AD$

substitute the values

$P=12+8+4+8=32\ cm$

step 5

Find the perimeter of trapezoid EFGH

we know that

If two figures are similar, then the ratio of its perimeters is equal to the scale factor

Let

z ---> the scale factor

x ----> the perimeter of trapezoid ABCD

y ----> the perimeter of trapezoid EFGH

so

$z=\frac{x}{y}$

we have

$z=\frac{2}{3}$

$x=32\ cm$

substitute

$\frac{2}{3}=\frac{32}{y}$

$y=32(3)/2=48\ cm$

therefore

The perimeter of trapezoid EFGH is 48 centimeters

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3 years ago

A house on the market was valued at $245,000. After several years, the value increased by 9%. By how much did the house's value

aniked [119]

We are given that a house had a value of $245000 and its value was increased by 9%. To determine how much is this value increase in dollars we need to multiply the value of the house by 9/100. We get this:

$245000\times\frac{9}{100}=22050$

Therefore, the increase in dollars is $22050. Now, to determine the current value we need to add the increase to the previous value, we get:

$245000+22050=267050$

Therefore, the current value of the house is $267050.

6 0

1 year ago

Help me please....

KIM [24]

Answer:

car a-50 kilos per hour

car b-55 kilos per hour

car b is faster

Step-by-step explanation:

150/3=50

220/4=55

3 0

3 years ago