Given :
A function , x = 2cos t -3sin t .....equation 1.
A differential equation , x'' + x = 0 .....equation 2.
To Find :
Whether the given function is a solution to the given differential equation.
Solution :
First derivative of x :

Now , second derivative :

( Note : derivative of sin t is cos t and cos t is -sin t )
Putting value of x'' and x in equation 2 , we get :
=(-2cos t + 3sin t ) + ( 2cos t -3sin t )
= 0
So , x'' and x satisfy equation 2.
Therefore , x function is a solution of given differential equation .
Hence , this is the required solution .
Answer:
a and c
Step-by-step explanation:
Answer:
I believe the correct answer would be A: 3/5 = 60
Step-by-step explanation:
Firstly, the second option is wrong because 0.06 would be 6 hundredths, so that is wrong, the third option would be incorrect because 0.002 would equal 2 thousandths so that is also wrong, and the fourth option would be 25% instead of 75%, so your answer should be A.