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2 years ago

Jerold put a desk in his bedroom. The picture shows where he put the desk. What is the area of the desk?

Mathematics

1 answer:

Kay [80]2 years ago

4 0

$18feet {}^{2}$
just count the squares it takes up

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2 less than the square of a number.

olasank [31]

Answer:

n²-2

Step-by-step explanation:

Let's let n stand for a number. 2 less than a square of a number, that means, the result of n²-2 is two less than n². I hope this makes sense!

7 0

2 years ago

If I get 27 questions correct and the percent is 90 how many questions are there?

Mamont248 [21]

27 is 90% of 30. Hope that helps.

6 0

2 years ago

How do you find out a Pythagorean triple?

____ [38]

383 83&93838+3339(902)

4 0

2 years ago

The following sample was collected during registration at a large middle school. At the 0.05 level of significance, can it be co

larisa [96]

Answer:

use Ma.thway it helps

Step-by-step explanation:

7 0

2 years ago

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

2 years ago