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Nady [450]
3 years ago
6

Write an equation of the line that passes through (-2, 0) and is perpendicular to the line y=-1/3x+3

Mathematics
1 answer:
Virty [35]3 years ago
8 0

Slope of y = -⅓x + 3 is -⅓ (on comparing with m of y = mx + c)

As the required line is perpendicular to this, slope of the required line = - 1 / (-⅓) = 3

Equation:

=> y - y1 = m(x - x1)

=> y - 0 = (3)(x - (-2))

=> y = 3(x + 2)

=> 3x - y + 6 = 0

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zalisa [80]
<h2>♪Answer : </h2>

Ingat rumus determinan fungsi kuadrat yaitu :

\longmapsto\boxed{\sf{D = b^2 - 4ac}}

Maka, Kita kembali jawab soalnya.

⏩Nomor (1) :

»8x² + 7x + 10 = 0

Didapatkan nilai² a, b, dan c yaitu :

  • a = 8 | b = 7 | c = 10

Maka, nilai determinannya adalah

  • D = b² - 4ac
  • D = 7² - 4(8)(10)
  • D = 49 - 4(80)
  • D = 49 - 320
  • D = -271✅

\:

⏩Nomor (2) ;

»2x² + 10x + 10 = 5

»2x² + 10x + 10 - 5 = 0

»2x² + 10x + 5 = 0

Didapatkan nilai² a, b, dan c yaitu :

  • a = 2 | b = 10 | c = 5

Maka, nilai determinannya adalah

  • D = b² - 4ac
  • D = 10² - 4(2)(5)
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  • D = 100 - 40
  • D = 60✅
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2 years ago
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