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REY [17]
2 years ago
8

Two percent of the customers of a store buy cigars. Half of the customers who buy cigars buy beer. 25 percent who buy beer buy c

igars. Determine the probability that a customer neither buys beer nor buys cigars.
Mathematics
1 answer:
enyata [817]2 years ago
4 0

Answer:

0.95

Step-by-step explanation:

The computation of the probability that a customer neither buys beer nor buys cigars is given below;

Given that, the probabilities are

The customers who purchased cigars be 0.02

The customers who purchased cigars + beer 0.50

And, the customers who purchased beer + cigars be 0.25

Now the probabilities where the customer purchased both

= 0.05 × 0.02

= 0.10

The probability where the customer purchased beer is

= 0.01 ÷ 0.25

= 0.04

Now the probability where a customer neither buys beer nor buys cigars is

= 1 - 0.02 + 0.04 - 0.01

= 0.95

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Step-by-step explanation:

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Therefore 3x + 2 + 6x - 20 = 180.

=> 9x - 18 = 180

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3 0
3 years ago
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Nataly_w [17]

For this case we have that the expression in its exact form is the same, that is:

5 \sqrt {10}

If it is expressed in decimal form we have:

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If we want equivalent expressions, we must first mention the following property of powers and roots:

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Then, we can rewrite the expression as:

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8 0
3 years ago
Given: 2x^2+3x-5, g(x)=x+9. Find: (fg)(3)
Svetradugi [14.3K]

Answer:

264

Step-by-step explanation:

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2 years ago
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5 0
3 years ago
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tatiyna

Let a,b,c,d and e are five numbers

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now, Let the number excluded be a

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⇒ (b+ c+ d+e)= 112

putting this value in (1),

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⇒a = 150 -112 = 38

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4 0
2 years ago
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