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Julli [10]
4 years ago
13

7. Find the mean, median, mode and range of the data set after you perform the given operation on each data value.

Mathematics
2 answers:
nydimaria [60]4 years ago
4 0
7.
Mean = 104
Median = 14
Mode = 14
Range = 30
8.
Mean = 20.41
Median = 17
Mode = 13
Range = 8
Nana76 [90]4 years ago
3 0

Answer with Step-by-step explanation:

Mean=sum of all observations/number of observations

Median=middle term of all observations arranged in ascending order

Mode=observation with highest frequency(the observation which is repeated so many times)

Range=largest observation subtracted by the smallest

7)    14, 7, 34, 29, 14, 6

multiply by 6

84,42,204,174,84,36

Arranging in ascending order

36,42,84,84,174,204

Mean=104

Median=84

Mode=84

Range=168

8)   13, 17, 15, 18, 21, 13, 20

add 3.7

16.7,20.7,18.7,21.7,24.7,16.7,23.7

arranging in ascending order

16.7,16.7,18.7,20.7,21.7,23.7,24.7

Mean=20.41

Median=20.7

Mode=16.7

Range=8

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Find the distance between -4 and 10 on a<br> number line.
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Answer:

14 numbers.

Step-by-step explanation:

Since -4 is in the negatives, we would go up on the number line until we reached positive 10. Which would therefore equal, 14.

6 0
3 years ago
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In a one-way ANOVA, the __________ is calculated by taking the squared difference between each person and their specific groups
guapka [62]

Answer:

In a one-way ANOVA, the SS_{within} is calculated by taking the squared difference between each person and their specific groups mean, while the SS_{between} is calculated by taking the squared difference between each group and the grand mean.

Step-by-step explanation:

The one-way analysis of variance (ANOVA) is used "to determine whether there are any statistically significant differences between the means of two or more independent groups".

The sum of squares is the sum of the square of variation, where variation is defined as the spread between each individual value and the mean.

If we assume that we have p groups and each gtoup have a size n_j then we have different sources of variation, the formulas related to the sum of squares are:

SS_{total}=\sum_{j=1}^{p} \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2

A measure of total variation.

SS_{between}=\sum_{j=1}^{p} n_j (\bar x_{j}-\bar x)^2

A measure of variation between each group and the grand mean.

SS_{within}=\sum_{j=1}^{p} \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2

A measure of variation between each person and their specific groups mean.

8 0
3 years ago
Find the value of each trigonometric ratio to the nearest ten-thousandth.
julsineya [31]
Sin C draw a line from C to the opposite side 21 and hypotenuse is the long side
Answer 21/29
5 0
4 years ago
Points S (-4, 6) and R (1,7) line on line SR. If points S' and R' are created by
Damm [24]

Answer:

A. 1/5

1/5 in fraction form

or

0.2 in decimal form

Step-by-step explanation:

slope (m)= 1/5 = 0.2

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3 0
4 years ago
) Determine the probability that a bit string of length 10 contains exactly 4 or 5 ones.
yanalaym [24]

Answer: 0.4512

Step-by-step explanation:

A bit string is sequence of bits (it only contains 0 and 1).

We assume that the  0 and 1 area equally likely to any place.

i.e. P(0)= P(1)= \dfrac{1}{2}

The length of bits : n = 10

Let X = Number of getting ones.

Then , X \sim Bin(n=10,\ p=\dfrac{1}{2})

Binomial distribution formula : P(X=x)=^nC_x p^x q^{n-x} , where p= probability of getting success in each event and q= probability of getting failure in each event.

Here , p=q=\dfrac{1}{2}

Then ,The probability that a bit string of length 10 contains exactly 4 or 5 ones.

P(X= 4\ or\ 5)=P(x=4)+P(x=5)\\\\=^{10}C_4(\dfrac{1}{2})^{10}+^{10}C_4(\dfrac{1}{2})^{10}

=\dfrac{10!}{4!6!}(\dfrac{1}{2})^{10}+\dfrac{10!}{5!5!}(\dfrac{1}{2})^{10}

=(\dfrac{1}{2})^{10}(\dfrac{10!}{4!6!}+\dfrac{10!}{5!5!})

=(\dfrac{1}{2})^{10}(210+252)

=(0.0009765625)(462)

=0.451171875\approx0.4512

Hence, the  probability that a bit string of length 10 contains exactly 4 or 5 ones is 0.4512.

3 0
4 years ago
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