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Papessa [141]
3 years ago
11

Select all of the following equations that would have the point (4, 16) located on their graph.

Mathematics
1 answer:
geniusboy [140]3 years ago
3 0
The 3, 4, and 5 :) hope it helps
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Which expression is equivalent to 16 - 4x^2?
melamori03 [73]

Answer:

4(2 - x)(2 + x)

Step-by-step explanation:

16 - 4x² ← factor out 4 from each term

= 4(4 - x²) ← difference of 2 squares

= 4(2 - x)(2 + x) ← in factored form

8 0
3 years ago
Choose the equation below that represents the line passing through the point (1, -- 4) with a slope of 1/2. (1 point)
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I think it’s the first one is not sure tho
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What is the value of the expression 4/7 ÷ 12/21
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Your answer is 1
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6 0
3 years ago
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A photo of a beetle in a science book is increased to 535​% as large as the actual size. If the beetle is 14 ​millimeters, what
AnnZ [28]

Answer: 74.9 millimeters

Step-by-step explanation:

From the question, a photo of a beetle in a science book was.increased to 535​% as large as its actual size and the beetle.has a actual size of 14 ​millimeters,

The size of the beetle on the photo will be 535% of 14 millimeters. This will be:

= 535% of 14

= 535/100 × 14

= 5.35 × 14

= 74.9 millimeters

4 0
3 years ago
Suppose it is known that 60% of radio listeners at a particular college are smokers. A sample of 500 students from the college i
vladimir1956 [14]

Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers

The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=500\times 0.60=300>10\\n(1-p)=500\times(1-0.60)=200>10

Thus, a Normal approximation to binomial can be applied.

So,  

X\sim N(\mu=600, \sigma=\sqrt{120})

Compute the probability that at least 280 of these students are smokers as follows:

Apply continuity correction:

P (X ≥ 280) = P (X > 280 + 0.50)

                   = P (X > 280.50)

                   =P(\frac{X-\mu}{\sigma}>\frac{280-300}{\sqrt{120}}\\=P(Z>-1.83)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

8 0
3 years ago
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