Answer:
here's the graph
Step-by-step explanation:
Answer:
106
Step-by-step explanation:
1272/21
Answer:
<u>x=6</u><u> y=16</u>
Step-by-step explanation:
I will use elimination
y=2x+4
y=2x+x-2
*3 y=2x+4 3y=6x+12
*2 y=3x-2 2y=6x-4
3y=6x+12
- 2y=6x. -4
<u>y=16</u>
16=2x+ 4
-4 -4
12= 2x
/2 /2
<u>6=x</u>
Answer:
Step-by-step explanation:
1S. JM bisects ∠ KJL and ∠JMK ≅ ∠JML
1R. Given
2S. ∠KJM ≅ ∠LJM
2R. Angle bisectors form ≅ ∠s
3S. JM≅JM
3R. Reflexive Propriety ( segment is ≅ with itself)
4S. ΔJMK ≅ΔJML
4R. ASA theorem of congruency
5S. JK≅JL
5R. Coresponding parts of congruent Δs are congruent (CPCTC)
Answer:
2855.0
Step-by-step explanation:
there are several surface areas.
1. outside surface of the cylinder = circle circumference times height = 2*pi*r*height = 2*pi*14*14 = 1231.5
2. top and bottom of the cylinder = circle area times 2 = pi*r^2 * 2 = pi*14^2 *2 = also 1231.5
3. subtract the 2 cut out rectangles on the top and the bottom = 2* 6*14 = 168
4. add the areas of the inside walls of the cut out block.
there are 2 narrow rectangles = 2* 6*14 = 168
there are 2 squares = 2* 14*14 = 392
so, 1.+2.-3.+4. = 2855.0 (2855.00864...)
