2x^2+20x=-38 divide both sides by 2
x^2+10x=-19, halve the linear coefficient, square it, than add that value to both sides of the equation, in this case add (10/2)^2=25...
x^2+10x+25=6 now the left side is a perfect square
(x+5)^2=6 take the square root of both sides
x+5=±√6 subtract 5 from both sides
x=-5±√6 (so answer c.)
Perimeter = 2L + 2W = 256
"8 feet longer than it is wide"
translates to
L = 8 + W
we plug that into the first equation and get
2(8 + W) + 2W = 256
now we solve for W
distribute the 2
16 + 2W + 2W = 256
add like terms
16 + 4W = 256
subtract 16 from both sides
4W = 240
divide both sides by 4
W = 60
plug that into
L = 8 + W
and solve for L now
L = 8 + 60
so
L = 68
therefore your
length = 68
and
width = 60
A) Sqrt(4^(2/3x)) * 2^x = 1
4^(1/3x) * 2^x = 1
2^(2/3x) * 2^x = 1
2^(5/3x) = 1
Log(2)1 = 5/3x
0 = 5/3x
x = 0
Answer:
10^5=100000
Step-by-step explanation:
The length of the median from vertex C is equal to √17. As a median of a triangle is a line segment joining a single vertex to the midpoint of the opposite side of the triangle. In this case, the median will be from vertex C to the mid-point of the triangles side AB.<span> Thus, we can work out the length of the median from vertex C by using the Midpoint formula; M(AB) = (X</span>∨1 + X∨2) /2 ; (Y∨1 + Y∨2) /2 . Giving us the points of the midpoint of side AB, which can be plotted on the cartesian plane. to find the length of the median from vertex C, we can use the distance formula and the coordinates of the midpoint and vertex C , d = √(X∨2 - X∨1) ∧2 + (Y∨2 - Y∨1)∧2.
