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3 years ago

Scientific Notation, if you could help that would be wonderful!

Mathematics

1 answer:

Umnica [9.8K]3 years ago

8 0

Answer:

1:D

2:A

3:C

4:E

5:B

Step-by-step explanation:

A negative exponent will be when you move the decimal point to the left. A positive exponent will be moving the decimal point to the right.

The number of the exponent is how many times you will move the decimal point.

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3 x 10^4 in standard form

Art [367]

Answer: 3x10=30

3x10(with the power of 2)=300

3x10(with the power of 3)=3000

3x10(witht the power of 4)=3000

Step-by-step explanation:

sorry if this dont help

6 0

2 years ago

What is 63×.04 as a decimal

liraira [26]

63 x .04 = 2.52

That is your answer to the question! Hope I helped :)

3 0

3 years ago

V + 9<br> ---------- = 8 <br> 3<br><br> Can someone help me ??

bagirrra123 [75]

$\frac{v + 9}{3} = 8$

Multiply both sides by 3, because 3 is our denominator (bottom number in a fraction), and we want to get rid of the denominator.

3 × (v + 9) = 8 × 3

Simplify.

3v + 27 = 24

Then, subtract both sides by 27.

3v = 24 - 27

Simplify.

3v = -3

Divide both sides by 3.

v = -1

~Hope I helped!~

4 0

3 years ago

How far above sea level is the ranger station?

Schach [20]

Since he descended 12 meters, we subtract this from the overall height of Mount Ka'ala, so then we are only calculating how high ABOVE the sea level it is.

1232 - 12 = 1220

The height of Mount Ka'ala is therefore 1,220 meters.
To calculate how much a fifth of Mount Ka'ala is (since the ranger station is 2/5's up), we would divide this number by 5

1220 ÷ 5 = 244

Since ONE fifth of the height is 244 meters, TWO fifths would be double that amount.

244 x 2 = 488

488 meters.
The ranger station is 488m above sea level.

3 0

3 years ago

A blimp provides aerial tv views of a soccer game. The camera sights the stadium at a 7 degree angle of depression. The altitude

maria [59]

Given that,

The camera sights the stadium at a 7 degree angle of depression.

The altitude of the blimp i slide 300 m.

To find,

The line of sight distance from the camera to the stadium.

Solution,

If we consider a right angled triangle. Let x is its hypotenuse i.e. the line of sight distance from the camera to the stadium. Using trigonometry :

$\sin\theta=\dfrac{P}{x}\\\\x=\dfrac{P}{\sin\theta}\\\\=\dfrac{300}{\sin7}\\\\=2461.65\ m$

So, the line of sight is at a distance of 2461.65 m from the camera to the stadium.

6 0

3 years ago