Answer: 1/30
Step-by-step explanation:
∫[0,4] arcsin(x/4) dx = 2π-4
x = 4sin(u)
arcsin(x/4) = arcsin(sin(u)) = u
dx = 4cos(u) du
∫[0,4] 4u cos(u) du
∫[0,4] f(x) dx = ∫[0,π/2] g(u) du
v = ∫[1,e] π(R^2-r^2) dx
where R=2 and r=lnx+1
v = ∫[1,e] π(4-(lnx + 1)^2) dx
Using shells dy
v = ∫[0,1] 2πrh dy
where r = y+1 and h=x-1=e^y-1
v = ∫[0,1] 2π(y+1)(e^y-1) dy
v = ∫[0,1] (x-x^2)^2 dx = 1/30
I'm going to say about 48 square yards.
I'm 50/50 chance wrong
Hope this helps c:
9514 1404 393
Answer:
24 m
Step-by-step explanation:
The area formula tells us ...
22 = xy . . . . . square meters
Adding twice this to the quadratic constraint gives ...
(x^2 +y^2) +2(xy) = (100) +2(22)
(x +y)^2 = 144
x +y = √144 = 12
The perimeter is double this amount, so is ...
P = 2(x +y) = 2(12) = 24 . . . . meters
Answer:
It could be 7π cm
Step-by-step explanation:
im sorry im not really sure
