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professor190 [17]
3 years ago
7

There are 448 reams of paper in thw supply room. Fourteen reams are used each day. At that rate, how many days will the supply o

f paper last?
Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
5 0
448 divided by 14 is 32 so 32 days
Mnenie [13.5K]3 years ago
3 0
X = number of days that have passed

448 = 14x

divide both sides by 14

32 = x
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A regular octagon rotates 360° about its center. How many times does the image of the octagon coincide with the preimage during
Elden [556K]
<span>A regular octagon is a closed figure with sides of the same length and internal angles of the same size. so if it is rotated 360 degrees it should coincide with its preimage after every 45 degrees. So 360/45= 8 times</span>
8 0
3 years ago
Read 2 more answers
90 Points!! PLEASE MAKE SURE THE INORMATION IS CORRECT THAT YOU GIVE ME!
jekas [21]

Answer:

They bought 23 tickets for children and 52 for adults.

Step-by-step explanation:

So first you must find what i represents so here it is

A= Adult

C= Children

They both sold the tickets which is going to be

A + C = 75

Now here it shows

12= each adult ticket

8= each children ticket

find the equation like this 12 A + 8C = 808

Now to find the C

You can find by resolving it like this

C= 75 - A

Solve the A and C

4A = 208

A = 52

12 (52) + 8C = 808

624 + 8C = 808

Children = 23

Adult= 52

8 0
3 years ago
Take two- HOW DO I SOLVE THISSSSSSSSS
DerKrebs [107]
The image is grey lol
7 0
3 years ago
1- find the first term= ?, 90, 540, 3240
Luda [366]

Answer:

1. 15

2. 8

Step-by-step explanation:

The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)

The nth term of a GP is;

Tn = ar^(n-1)

Where;

a = first term

r = common ratio

For the first sequence;

The common ratio r is

r = T3/T2 = 540/90 = 6

r = 6

T2 = ar^(2-1) = ar

T2 = 90 = ar

Substituting the values of r;

90 = a × 6

a = 90/6

a = 15

First term = 15

2. The sam method applies here.

Common ratio r = T3/T2 = 128/32 = 4

r = 4

T2 = ar^(2-1) = ar

T2 = 32 = ar

Substituting the values of r;

32 = a × 4

a = 32/4

a = 8

First term = 8

4 0
3 years ago
WHAT IS THE ANSWER FOR 12 1/3 + 8 3/4 +17 2/8 +23 2/3=
gulaghasi [49]
12  \dfrac{1}{3}  + 8  \dfrac{3}{4}  +17  \dfrac{2}{8}  +23  \dfrac{2}{3}

Simplify
= 12  \dfrac{1}{3}  + 8  \dfrac{3}{4}  +17  \dfrac{1}{4}  +23  \dfrac{2}{3}

Change the denominators to be the same
= 12  \dfrac{1 \times 4}{3 \times 4}  + 8  \dfrac{3 \times 3}{4 \times 3}  +17  \dfrac{1 \times 3 }{4 \times 3}  +23  \dfrac{2 \times 4}{3 \times 4}

= 12  \dfrac{4}{12}  + 8  \dfrac{9}{12}  +17  \dfrac{3 }{12}  +23  \dfrac{8}{12}

Combine into single fraction
= 60  \dfrac{24}{12}

= 62

6 0
3 years ago
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