Answer:
The sequence of first five terms
4 , 5, 6, 7, 8
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given 
of the sequence
aₙ = n + 3 ..(i)
put n =1
a₁ = 1 +3
a₁ = 4
The first term of the sequence = 4
Put n =2 in equation (i)
a₂ = 2+3
a₂ = 5
The second term of the sequence = 5
put n=3 in equation (i)
a₃ = 3+3 = 6
The third term of the sequence = 6
Put n=4 in equation (i)
a₄ = 4 +3
a₄ = 7
The fourth term of the sequence = 7
Put n = 5 in equation (i)
a₅ = 5+3
a₅ = 8
The fifth term of the sequence = 8
<u><em>Step(ii):-</em></u>
The sequence of first five terms
4 , 5, 6, 7, 8
A) 0.955 and 199/200
B) 1.40 or 1.4 and 1 2/5
C) 0.90 or 0.9 and 9/10
(3,52)(7,108)
slope = (108 - 52) / (7 - 3) = 56/4 = 14
y = mx + b
slope(m) = 14
(3,52)...x = 3 and y = 52
sub and find b, the y int (the original amount of cards)
52 = 3(14) + b
52 = 42 + b
52 - 42 = b
10 = b
so ur equation is y = 14x + 10....with x being the number of years and y being the total cards. <== ur equation is y = 14x + 10
He started with 10 cards....and has been adding 14 cards every year.
so after 10 years...
y = 14(10) + 10
y = 140 + 10
y = 150 <== after 10 years, he will have 150 cards
Answer:
Paul
Step-by-step explanation:
Paul earn more than monica. Though he is getting less interest but because of his higher initial amount he is getting more return.
Computing the return of both
Monica return is 100*3.4%= $3.4 in a year
Paul return is 200*%2.2= $4.4 in a year.
It will be the model that has the arrow going to the right with the starting point at 60 having a solid circle.
