Captain Ishaan has a ship, the H.M.S. Khan. The ship is two furlongs from the dread pirate Luis and his merciless

Mathematics

1 answer:

fredd [130]3 years ago

4 0

Answer:

Khan Academy's answer is 4/35.

Step-by-step explanation:

4/5 * 1/7 = 4/35

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The temperature in Tampa Fonda is 15 degrees warmer than twice the temperature in Chicago, Illinois. The temperature in Tampa is

k0ka [10]

The temp of Chicago is 30 degrees.

15 degree MORE than TWICE the temp of Chicago. 75-15=60/2. Hope this helps.

7 0

3 years ago

Read 2 more answers

Pre-Calc<br><br> Please help with the question highlighted in red

ololo11 [35]

Believe it or not, this is the second version of Q is very similar to the first, even though it doesn't really look like it. We can represent the second version as a * (1 + r)^t

See the similarity between this and the first version? Thus, we can represent what is given in the problem as:
Q = a * b^t = a * (1 + r)^t

Thus, b = 1 + r. Since b = 0.8, we can find r.
0.8 = 1 + r
r = -0.2, or r = -20%.

4 0

3 years ago

Weight gain during pregnancy. In 2004, the state of North Carolina released to the public a large data set containing informatio

pychu [463]

Answer:

1. B. H0: μ1−μ2=0, HA: μ1−μ2≠0

2. z=1.2114

3. P-value=0.2257

4. Do not reject H0

Step-by-step explanation:

We have to perfomr an hypothesis test to see if there is strong evidence that there is a significant difference between the two population means.

The null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2\neq0$

Being μ1 the mean average gain for younger mothers and μ2 the mean average gain for mature mothers.

(NOTE: we are comparing means, not proportions, as it is the random variable is the weight gain).

As we are claiming "strong evidence", the level of significance will be 0.01.

For younger mothers, the sample size is n1=840, the sample mean is 30.7 and the sample standard deviation is s1=14.91.

For mature mothers, the sample size is n2=132, the sample mean is 29.15 and the sample standard deviation is s2=13.46.

The difference between means is

$M_d=\mu_1-\mu_2=30.7-29.15=1.55$

The standard error of the difference between means is

$s_M=\sqrt{\dfrac{s_1^2}{n_1}+\dfrac{s_2^2}{n_2}}=\sqrt{\dfrac{14.91^2}{840}+\dfrac{13.46^2}{132}}=\sqrt{ 0.2647+1.3725}=\sqrt{1.6372}\\\\\\s_M=1.2795$