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2 years ago

Please help i will give brainleist Screen shot down below⬇⬇⬇

Mathematics

2 answers:

olasank [31]2 years ago

4 0

Answer: I think its B

Step-by-step explanation:

Over [174]2 years ago

3 0

Answer:

Step-by-step explanation:

i think its sependent variable

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A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300. The

zubka84 [21]

Answer:

the variance of the refund payment to the couple = 9463.394

Step-by-step explanation:

Given that :

A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300.

It is possible that the couple won't be able to refund up 100 per day or more than 100 per day.

SO; let assume that the refund payment happens to be 0, 100,200, 300

Let X be the total refund payment on the seven day cruise.

We can say X = 0, if there is no rain on all 7 days.

$P(X = 0) = _nC_x * P^x * (1 - P)n-x$

$P(X = 0) = _7C_o * 0.2^0 * (1-0.2)^{7-0$

$P(X = 0) =1 * 1* (1-0.2)^{7$

$P(X = 0) =(0.8)^{7$

$P(X = 0) =0.2097152$

If it rains on any one day; then X = 100

$P(X = 100) = _nC_x * P^x * (1 - P)n-x$

$P(X = 100) = _7C_1 * 0.2^1 * (1-0.2)^{7-1$

$P(X = 0) =7 * 0.2* (1-0.2)^{6$

$P(X = 100) =7* 0.2* (0.8)^{6$

$P(X = 100) =0.3670016$

if it rains on any two day ; then X = 200

$P(X = 200) = _nC_x * P^x * (1 - P)n-x$

$P(X = 200) = _7C_2 * 0.2^2 * (1-0.2)^{7-2$

$P(X = 200) = 21 * 0.2^2 * (0.8)^{5$

$P(X = 200) = 0.2752512$

if it rains on any three day or more than that ; then X = 300

$P(X \ge 300) = 1 - P(X < 300) \\ \\ P(X \ge 300) = 1 - [P(X = 0) + P(X = 100) + P(X = 200)] \\ \\ P(X \ge 300) = 1 - [0.2097152 + 0.3670016 + 0.2752512] \\ \\ P(X \ge 300) = 0.148032$

Now; we have our probability distribution function as:

P(X = 0) = 0.2097152

P(X = 100) = 0.3670016

P(X = 200) = 0.2752512

P(X = 300) = 0.148032

In order to determine the variance of the refund payment to the couple; we use the formula:

variance of the refund payment to the couple $[Var X] =E [X^2] - (E [X])^2$

where;

$E[X^2] = \sum x^2 \times p \\ \\ E[X^2] = 0^2 * 0.2097152 + 100^2 * 0.3670016 + 200^2 * 0.2752512 + 300^2 * 0.148032 \\ \\ E[X^2] = 0 + 3670.016 + 11010.048+ 13322.88 \\ \\ E[X^2] =28002.944$

$(E [X]) = \sum x * p\\ \\ (E [X]) = 0 * 0.2097152 + 100 * 0.3670016 + 200 * 0.2752512 + 300 * 0.148032 \\ \\ (E [X]) = 0 + 36.70016 + 55.05024 + 44.4096\\ \\ (E [X]) = 136.16 \\ \\ (E [X])^2 = 136.16^2 \\ \\ (E [X])^2 = 18539.55$

NOW;

the variance of the refund payment to the couple = 28002.944 - 18539.55

the variance of the refund payment to the couple = 9463.394

7 0

2 years ago

0: Shelby set a goal to run 3.1 miles. Today she ran 2.6 miles. What percent of her goal did she run?

alukav5142 [94]

Answer:

83.8% or 84%

Step-by-step explanation:

6 0

3 years ago

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Burka [1]

V=4x-1 I believe is the anwsers

4 0

2 years ago

Binomial factor of 25x2 + 40xy + 16y2 ?

Reika [66]

Answer:

(5x +4y)^2

Step-by-step explanation:

The first and last terms are both perfect squares, and the middle term is twice the product of their roots. That means the trinomial is the perfect square trinomial ...

25x^2 +40xy +16y^2 = (5x +4y)^2

_____

It matches the pattern ...

a^2 +2ab +b^2 = (a +b)^2

8 0

2 years ago

5x^2-(3xy-7x^2)+(5xy-12x^2)<br> When x=-0.25, and y=4

prohojiy [21]

$5x^2-(3xy-7x^2)+(5xy-12x^2)=5x^2-3xy+7x^2+5xy-12x^2=2xy\\\\ 2\cdot(-0.25)\cdot4=-2$

5 0

2 years ago

Read 2 more answers