Question

Polygon ABCD is translated to create polygon A’B’C’D’. Point A is located at (1,5), and point A’ is located at (-2,1). What is the distance from B to B’?

Answer 1

Answer:

The distance from B to B’ is $5\ units$

Step-by-step explanation:

we know that

In a translation the shape and dimensions of the figure are not going to change.

therefore

AA'=BB'=CC'=DD'

Find the distance AA'

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

$A(1,5)\\A'(-2.1)$  

substitute the values

$AA'=\sqrt{(1-5)^{2}+(-2-1)^{2}}$

$AA'=\sqrt{(-4)^{2}+(-3)^{2}}$

$AA'=\sqrt{25}$

$AA'=5\ units$

therefore

$BB'=5\ units$