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2 years ago

У + 8 = (x — 1)

Mathematics

1 answer:

nikitadnepr [17]2 years ago

5 0

Answer:

slope: 1

point: (1,-8)

Step-by-step explanation:

The equation is given in point-slope form:

$y-y_{1}=m(x-x_{1})$

The slope is the number in front of the (x-1). Because there's no actual number there, the slope is 1 (because 1(x-1) = (x-1). So the slope is 1.

From the point-slope formula, the point is (1, -8).

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Matter is in a liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance

a_sh-v [17]

Answer:

i. When the temperature is above $616.712^{o}$ F, it changes to gas.

ii. When the temperature is below $-33.052^{o}$ F, it changes to solid.

Step-by-step explanation:

Matter generally exists in either a solid, liquid or gaseous form. With each phase having a certain range of temperature.

Temperature scale of a given substance can be either in Celsius, Fahrenheit or Kelvin. And conversion from one scale to another can be achieved. Example, Celsius scale can be converted to Fahrenheit by:

F = $\frac{9}{5}$ θ + 32

where: F is the equivalent temperature in Fahrenheit, θ is the value of temperature in degree Celsius.

Given that: melting point of the substance = $-36.14^{o}$ C

⇒ F = $\frac{9}{5}$ x $-36.14^{o}$ + 32

= $-33.052^{o}$ F

The boiling point = $324.84^{o}$ C

F = $\frac{9}{5}$ x $324.84^{o}$ + 32

= $616.712^{o}$ F

The melting point of the substance is $-33.052^{o}$ F, and boiling point is $616.712^{o}$ F.

Therefore, the range of temperatures for which the substance is not in a liquid state are:

i. When the temperature is above $616.712^{o}$ F, it changes to gas.

ii. When the temperature is below $-33.052^{o}$ F, it changes to solid.

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Chuge%7B%5Cgreen%7D%5Cfcolorbox%7Bblue%7D%7Bcyan%7D%7B%5Cbf%7B%5Cunderline%7B%5Cred%7B%5C

MariettaO [177]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's find out the gradient (Slope " m ") of line q ;

$\qquad \sf \dashrightarrow \:m = \dfrac{y_2 - y_1}{x_2 - x_1}$

$\qquad \sf \dashrightarrow \:m = \dfrac{4 - 0}{0 - 1}$

$\qquad \sf \dashrightarrow \:m = - 4$

Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :

$\qquad \sf \dashrightarrow \:y - 4 = m(x - 0)$

$\qquad \sf \dashrightarrow \:y = mx + 4$

Now, plug in the value of gradient ~

$\qquad \sf \dashrightarrow \:y = - 4x + 4$

here we can clearly observe that, the Area under the curve can easily be represented as :

$\qquad \sf \dashrightarrow \:y < - 4x + 4$

Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q

5 0

2 years ago

Can someone explain how to graph this? I know how to graph it in the y= format. So can someone explain how to get these equation

artcher [175]

Answer:

hope this helps.

Step-by-step explanation:

You don't really need to get them in the y format.

make a table and plug some numbers in and graph those points

use a ruler to connect the dots.

y = -3 is a horizontal line

8 0

3 years ago

Simplify the answer pls

disa [49]

Answer:

Step-by-step explanation:

24/3 - 4

8 - 4 = 4

4 0

3 years ago

What is absolute value

jeka94

Absolute value is the distance between a point and 0. Absolute value is always positive. When you're writing numbers in absolute value, make sure you add:

| |

The absolute value of a negative number is also positive. For example:

| -7 | = 7 ⇒The absolute value of -7 is 7.

3 0

3 years ago