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BabaBlast [244]
3 years ago
14

Find the zero of the polynomial p(x) = 3x + 5​

Mathematics
2 answers:
klasskru [66]3 years ago
8 0

Hope this helps. If it did please mark me brainliest

Answer:

A zero of the polynomial p(x) = 3x + 5 will be a value of x for which p(x) becomes 0. Dividing by 3, to get the value of x, we get: x=−53 , which is the zero of the given polynomial

pochemuha3 years ago
7 0

Answer:

\huge\boxed{Answer\hookleftarrow}

p(x) = 3x + 5

Zero of the polynomial,

3x + 5 = 0 \\ 3x =  0 - 5 \\ 3x =  - 5 \\ x =  \frac{ - 5}{3}  \\ x =  - 1.66

✐ The zero of the polynomial p(x) = 3x + 5 is <u>-5/3 (fraction form) OR - 1.66 (standard form).</u>

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

# ꧁❣ RainbowSalt2²2² ࿐

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Two altitudes of a triangle have lengths $12$ and $14$. What is the longest possible integer length of the third altitude
nataly862011 [7]

The longest possible altitude of the third altitude (if it is a positive integer) is 83.

According to statement

Let h is the length of third altitude

Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.

From Area of triangle

A = 1/2*B*H

Substitute the values in it

A = 1/2*a*12

a = 2A / 12 -(1)

Then

A = 1/2*b*14

b = 2A / 14 -(2)

Then

A = 1/2*c*h

c = 2A / h -(3)

Now, we will use the triangle inequalities:

  • a < b+c

2A/12 < 2A/14 + 2A/h

Solve it and get

h<84

  • b < a+c

2A/14 < 2A/12 + 2A/h

Solve it and get

h > -84

  • c < a+b

2A/h < 2A/12 + 2A/14

Solve it and get

h > 6.46

From all the three inequalities we get:

6.46<h<84

So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.

Learn more about TRIANGLE here brainly.com/question/2217700

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