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3 years ago

Find the slope of a line with the given points (0, 2) and (5, 0) *

Mathematics

2 answers:

Leno4ka [110]3 years ago

7 0

Answer:

I cant see the slopos so I cant slove sorry

Step-by-step explanation:

vagabundo [1.1K]3 years ago

3 0

Answer:

(2,1) or (1,2)

Step-by-step explanation:

I used the formula (x1+x2)/2 , (y1+y2)/2

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Express the measurement 4.29478416 kg with 8, 6, 4, and 2 significant figures

ira [324]

Significant figures refers to digits within a number which must be included in other depict correct quantity of the figure.

4.29478416 = 4.2947842 ( 8 significant figures)
4.29478416 = 4.29478 (6 significant figures)
4.29478416 = 4.295 ( 4 significant figures)
4.29478416 = 4.3 (2 significant figures)

To round a number to a certain number of significant figures,

Only leading 0 which comes before the decimal Point are regarded as insignificant.
Once the number of significant figures have been identified, the next number after this is either rounded up to 1 and added to the last value(if number is ≥5) or rounded to 0 (if number is less than 5)

Learn. More : brainly.com/question/13386983?referrer=searchResults

3 0

3 years ago

What is the equation of the line parallel to x = 7, passing through the point (-4, 1)? A. X = -4 B. X = 1 C. Y = -4 D. Y = 1

77julia77 [94]

Answer:

x=-4

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A certain drug is made from only two ingredients: compound A and compound B. There are 2 milliliters of compound A used for ever

GrogVix [38]

The answer is 435 milliliters

6 0

3 years ago

2x² - 5x+1 has roots alpha and beta. Find alpha⁴+beta⁴ without solving the equation.

shepuryov [24]

Answer:

Step-by-step explanation:

$\alpha+\beta=\dfrac{5}{2} \\\\\alpha*\beta=\dfrac{1}{2} \\\\\alpha^2+\beta^2=\dfrac{21}{4} \ (see\ previous\ post)\\\\(\alpha+\beta)^4=\dfrac{625}{16} \\\\=\alpha^4+\beta^4+4*\alpha^3*\beta+6*\alpha^2*\beta^2+4*\alpha*\beta^3\\\\=\alpha^4+\beta^4+4*(\alpha*\beta)(\alpha^2+\beta^2)+6*\alpha^2*\beta^2\\\\\alpha^4+\beta^4=(\alpha+\beta)^4-4*(\alpha*\beta)(\alpha^2+\beta^2)-6*\alpha^2*\beta^2\\\\= \dfrac{625}{16} -4*\dfrac{1}{2} *\dfrac{21}{4} -6*(\dfrac{1}{2})^2 \\\\$

$= \dfrac{625}{16}- \dfrac{168}{16}-\dfrac{24}{16}\\\\\\= \dfrac{433}{16}$

7 0

3 years ago

There are two positive numbers. four times the small number plus 3 times the big number is 41. two times the small number plus t

xxTIMURxx [149]

The small number is 2 the large number is 11.
4(2)+11(3)=41
2(2)+11=15
11(10) -2(6) = 98

hope that helps

4 0

3 years ago