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3 years ago

Find b: If a = 9 and c = 15 С a b

Mathematics

2 answers:

Alex17521 [72]3 years ago

7 0

I think it’s 6 I’m not 100% sure but I think it’s 6 cause if you subtract 9 and 15 it makes 6 but I’m not sure

pogonyaev3 years ago

3 0

Answer:

b=12

Step-by-step explanation:

a^2+b^2=c^2

(9×9) + b^2= 15×15

81+ b^2= 225

-81. -81

b^2=144

√. √

b= 12

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Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu

Alisiya [41]

Let $y=C_1x+C_2x^3=C_1y_1+C_2y_2$ . Then $y_1$ and $y_2$ are two fundamental, linearly independent solution that satisfy

$f(x,y_1,{y_1}',{y_1}'')=0$
$f(x,y_2,{y_2}',{y_2}'')=0$

Note that ${y_1}'=1$ , so that $x{y_1}'-y_1=0$ . Adding $y''$ doesn't change this, since ${y_1}''=0$ .

So if we suppose

$f(x,y,y',y'')=y''+xy'-y=0$

then substituting $y=y_2$ would give

$6x+x(3x^2)-x^3=6x+2x^3\neq0$

To make sure everything cancels out, multiply the second degree term by $-\dfrac{x^2}3$ , so that

$f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y$

Then if $y=y_1+y_2$ , we get

$-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0$

as desired. So one possible ODE would be

$-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0$

(See "Euler-Cauchy equation" for more info)

6 0

3 years ago

Can you help I have tried 4 times

Aleonysh [2.5K]

Answer:

426

Step-by-step explanation:

320 pounds is = to 5120 ounces there are 12 months in a year so 5120 divided by 12 is 426

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3 years ago

Read 2 more answers

Please please help ASAP

Dvinal [7]

Answer:

I think it's obtuse hope this helped have an amazing day

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Igoryamba

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Step-by-step explanation:

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fenix001 [56]

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