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2 years ago

Which of the following was a primary reason France sought to colonize North America?

Mathematics

1 answer:

slega [8]2 years ago

4 0

Answer: The answer is C on Quizizz.

Step-by-step explanation:

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Solve each trigonometric equation such that 0 ≤ x ≤ 2????. Give answers in exact form.

sveticcg [70]

Answer:

(a) $x=\frac{5\pi }{3}$

(b) $x=\frac{\pi }{8}$

Step-by-step explanation:

It is given that $0\leq x\leq 2\pi$

(a) We have given equation $2sinx+\sqrt{3}=0$

$sinx=\frac{-\sqrt{3}}{2}$

$x=sin^{-1}(-0.866)$

$x=\frac{-\pi }{3}=2\pi -\frac{\pi }{3}=\frac{5\pi }{3}$

(b) $tan(2x)=1$

$2x=tan^{-1}1$

$2x=\frac{\pi }{4}$

$x=\frac{\pi }{8}$

7 0

3 years ago

18% of the the students at a school are in year 8 and 16% of the students are in year 9. If the school has 126 tera 8 students,

yarga [219]

Answer:

112

Step-by-step explanation:

The general form of all percentage questions is: the chunk= (some percentage) (of the whole), or c=p*w

We know that 18% of students are 8th grade and that is 126 students, so p = 0.18 and c=126 (126 students are 18% of the whole school)

126 = (0.18)w, divide both sides by 0.18

126/(0.18) = w = 700

9th graders are 16% of the school or 16% of 700 students

c = (0.16) 700 = 112 students

5 0

2 years ago

Order the numbers from greatest to least.<br> 332 233 323

Hitman42 [59]

Answer:

Step-by-step explanation:

332 323 233

4 0

2 years ago

Read 2 more answers

Osvoldo has a goal of getting at least 30%, percent of his grams of carbohydrates each day from whole grains.

Pachacha [2.7K]

To answer this you need to figure out what 30% of the total number of carbs need to be whole-grain. Multiply 0.3 times 220 to get 66 grams. He did not meet his goal. Because he only ate 5 g, this is 61 less than he needs to meet his goal.

4 0

3 years ago

4sin²<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B2%7D" id="TexFormula1" title="\frac{x}{2}" alt="\frac{x}{2}" align="absm

raketka [301]

Answer:

$\displaystyle x=\left \{\frac{2\pi}{3}+2\pi k,\frac{4\pi}{3}+2\pi k, \frac{8\pi}{3}+2\pi k, \frac{10\pi}{3}+2\pi k\right \}k\in \mathbb{Z}$

Step-by-step explanation:

Hi there!

We want to solve for $x$ in:

$4\sin^2(\frac{x}{2})=3$

Since $x$ is in the argument of $\sin^2$ , let's first isolate $\sin^2$ by dividing both sides by 4:

$\displaystyle \sin^2\left(\frac{x}{2}\right)=\frac{3}{4}$

Next, recall that $\sin^2x$ is just shorthand notation for $(\sin x)^2$ . Therefore, take the square root of both sides:

$\displaystyle \sqrt{\sin^2\left(\frac{x}{2}\right)}=\sqrt{\frac{3}{4}},\\\sin\left(\frac{x}{2}\right)=\pm \sqrt{\frac{3}{4}}$

Simplify using $\displaystyle \sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}$ :

$\displaystyle \sin\left(\frac{x}{2}\right)=\pm \sqrt{\frac{3}{4}},\\\sin\left(\frac{x}{2}\right)=\pm \frac{\sqrt{3}}{\sqrt{4}}=\pm \frac{\sqrt{3}}{2}$

Let $\phi = \frac{x}{2}$ .

<h3><u>Case 1 (positive root):</u></h3>

$\displaystyle \sin(\phi)=\frac{\sqrt{3}}{2},\\\phi = \frac{\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\phi =\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z}$

Therefore, we have:

$\displaystyle \frac{x}{2}=\phi = \frac{\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\frac{x}{2}=\phi =\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z},\\\\\begin{cases}x=\boxed{\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z}},\\x=\boxed{\frac{4\pi}{3}+2\pi k , k \in \mathbb{Z}}\end{cases}$

<h3><u>Case 2 (negative root):</u></h3>

$\displaystyle \sin(\phi)=-\frac{\sqrt{3}}{2},\\\phi = \frac{4\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\phi =\frac{5\pi}{3}+2\pi k, k\in \mathbb{Z},\\\begin{cases}x=\boxed{\frac{8\pi}{3}+2\pi k, k\in \mathbb{Z}},\\x=\boxed{\frac{10\pi}{3}+2\pi k , k \in \mathbb{Z}}\end{cases}$

8 0

2 years ago