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Wittaler [7]
3 years ago
9

Complete the equation describing how x and y are related.

Mathematics
1 answer:
love history [14]3 years ago
6 0
X is horizontal while y is vertical
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The graph represents function 1, and the equation represents function 2: Function 2 y = 8x + 12 How much more is the rate of cha
nikklg [1K]
You don't have a picture posted for the graph, I'd assume its 5 (: if you attach an image with the graph, Id be happy to give a more clear answer. Good luck! :P
7 0
3 years ago
Can someone help me I give you 10 points
natka813 [3]

Answer:

A:40%

B:7.8

Step-by-step explanation:

Using a proportion , you can solve for the bottom side.

13/19.5 = 5.2/x

multiply 19.5 and 5.2 and rewrite the equation

101.4=13x

x=7.8

To find the scale, divide 5.2 by 13

5.2/13=0.4

Double check by dividing 7.8 by 19.5

7.8/19.5=0.4

0.4=40%

7 0
3 years ago
Will give brainiest, need help
eimsori [14]

Answer:

f(6) = 53

Step-by-step explanation:

f(x) = 10x - 7

We want to find f(6)

To do so simply substitute 6 for x in the equation

Equation: 10x - 7

x = 6

f(6) = 10(6) - 7

multiply 10 and 6

f(6) = 60 - 7

subtract

f(6) = 53

8 0
3 years ago
Read 2 more answers
Can u guys help me on number 3??? Plz
Goshia [24]
Well, since 3 cups is 2/5, 1 1/2 cups is 1/5. To get 5/5, or the full value of the water bottle, you must multiply 1 1/2 cups, or 1/5 of the full water bottle, which is 7 1/2 cups, so the answer is 7 1/2 cups.
7 0
4 years ago
For the matrices below. Find all (real) eigenvalues. <br><br> A= [7 9]<br> [0 9]
Jet001 [13]

Answer:

The answer is "9 and 7".

Step-by-step explanation:

Given:

A=\left[\begin{array}{cc}7&9\\0&9\end{array}\right]

Using formula:

|A-\lambda \cdot I|= 0\\\\

\to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]-\lambda \left[\begin{array}{cc}1&0\\0&1\end{array}\right] |=0\\\\\\ \to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]- \left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right] |=0\\\\\\\to|\left[\begin{array}{cc}7-\lambda &9\\0&9-\lambda\end{array}\right]|=0\\\\\\\to|(7-\lambda)(9-\lambda)|=0\\\\\to (7-\lambda)(9-\lambda)=0\\\\\to 7-\lambda=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9-\lambda=0\\\\

\to \lambda=7 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \lambda=9\\\\

8 0
4 years ago
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