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MariettaO [177]
3 years ago
15

Will give brainiest, need help

Mathematics
2 answers:
eimsori [14]3 years ago
8 0

Answer:

f(6) = 53

Step-by-step explanation:

f(x) = 10x - 7

We want to find f(6)

To do so simply substitute 6 for x in the equation

Equation: 10x - 7

x = 6

f(6) = 10(6) - 7

multiply 10 and 6

f(6) = 60 - 7

subtract

f(6) = 53

bearhunter [10]3 years ago
3 0

Answer:

f(x)=53

Step-by-step explanation:

For f(x)=10x-7\\ substitute x for 6

10\cdot 6=60\\60-7=53

f(6)=53

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WILL GIVE BRAINLEIST
DanielleElmas [232]

Answer: Last option ("Each term in the second sequence is one-third the corresponding term in the first sequence.")

Explanation:

First, you need to understand what the rules are saying. I find it useful to write them as equations, but everyone's different. Especially for this situation, making a table should be really helpful.

Rule 1: add 6 starting from 0

Add 6 each time. The "add" part should tell you that it's the slope. The equation has a slope of 6. "Starting from 0" tells you that the y-intercept is 0. Using slope-intercept form (y=mx+b, where m is the slope and b is the y-intercept), you can write the equation as y=6x+0, or y=6x.

Rule 2: add 2 starting from 0

2 is the slope and 0 is the y-intercept. y=2x

You didn't <em>have</em> to do this part, but it makes the rules easier to understand. Now you can easily make a table to find the relationship between the rules. First, pick some values of x to use:

Rule 1:

x  |    1   |   2  |   3

y  |         |       |

Rule 2:

x  |    1   |   2  |   3

y  |         |       |

(They're supposed to be tables with only the x-values filled in.)

Using the equations, or only the rules, you can fill in the tables.

You can use more than 3 values of x, but I think this is enough.

x=1:

Rule 1: y=6x

             =6(1)

            =6

Rule 2: y=2x

              =2(1)

              =2

Do the same thing for y when x=2 and x=3. Then you can fill in the tables to get:

Rule 1:

x  |    1   |   2  |   3

y  |    6  |  12  |   18

Rule 2:

x  |    1   |   2  |   3

y  |    2  |   4  |   6

Since you've organized the values now, it'll be much simpler to find the relationship between the rules. Observe the y-values.

When x=1, rule 1 results in 6, and rule 2 results in 2. Now look at each option in the answers.

"Each term in the second sequence is three times the corresponding term in the first sequence."

In the first sequence, you have 6 when x=1. If the corresponding term in the second sequence has to be 3 times that, it would have to be 18. This one doesn't work.

"Each term in the first sequence is one-third the corresponding term in the second sequence."

This is saying the same thing as the previous option. It doesn't work.

"Each term in the first sequence is six times the corresponding term in the second sequence."

When x=1, y in the second sequence is 2. 6 times that is 12, but the value in the first sequence is only 6. This option is incorrect as well.

"Each term in the second sequence is one-third the corresponding term in the first sequence."

2/6=1/3, so this one does work. You could have arrivived at this conclusion earlier by just dividing, but I wanted to explain why the rest don't work.

Hope I could help!

4 0
3 years ago
The Blue Diamond Company advertises that their nut mix contains (by weight) 40% cashews, 15% Brazil nuts, 20% almonds and only 2
jek_recluse [69]

Answer:

At the 0.05 level of significance,  the claim made by Blue Diamond is true

Step-by-step explanation:

Given that the Blue Diamond Company advertises that their nut mix contains (by weight) 40% cashews, 15% Brazil nuts, 20% almonds and only 25% peanuts.

H_0: The mix are as per percents given\\H_a:Atleast two differ from the above percent.

(Two tailed chi square test at 5% significance level)

Chi square is calculated as (Obs_exp)^2/Expected

Cashews Brazil nuts Almonds Peanuts Total

Observed 5 6 6 3 20

Expected  40% 15% 20% 25% 1

Expected  8 3 4 5 20

     

Chi square 1.125 3 1 0.8 5.925

df = 3

p value = 0.1153

Since p value >0.0 we accept null hypothesis.

4 0
3 years ago
Read each relationship and decide whether its graph would be continuous or discrete
Afina-wow [57]
The ones which are discrete would have answers like 1234 and would not have any decimal answers so you can’t have half a student or half a chair there for those of the two that are discrete
5 0
3 years ago
Who tryna help me lmaaoo
mina [271]
It is b ok I got you
7 0
2 years ago
Copy the problems onto your paper, mark the given and prove the statements asked. Given: marked Prove: ΔABC ≅ ΔDBC, ΔEHF ≅ ΔGHF
hjlf

The proof is given below. Please go through it.

Step-by-step explanation:

To solve Δ ABC ≅ Δ DBC

From Δ ABC and Δ DBC

AB = BD (given)

AC = CD (given)

BC is common side

By SSS condition Δ ABC ≅ Δ DBC ( proved)

To solve Δ EHF ≅ Δ GHF

Δ EHF and Δ GHF

EH = HG ( given)

∠ EFH = ∠ GFH ( each angle is 90°)

HF is common side

By RHS condition

Δ EHF ≅ Δ GHF

7 0
4 years ago
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