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OLEGan [10]
3 years ago
9

PWEASE HELP MWEEEEE UwU

Mathematics
1 answer:
Paha777 [63]3 years ago
4 0

Answer: the second

one

Step-by-step explanation:

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Y=2x−1
lord [1]

Answer:

(1,1) is a solution of the system.

Step-by-step explanation:

Let's solve the system.

y = 2x - 1

5x - 4y = 1

In the first equation, y is already separated as a function of x. So we replace in the second equation;

5x - 4(2x - 1) = 1

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5 0
3 years ago
In a study relating the degree of warping, in mm, of a copper plate (y) to temperature in °C (x), the following summary statisti
elena-14-01-66 [18.8K]

Answer:

a)

y = 0.3035 + 0.0082x

b)

0.6315 mm

c)

x = 23.9634 °C

Step-by-step explanation:

a. Compute the least-squares line for predicting warping from temperature. Round the answers to four decimal places.

We need to find an equation of the form

y = b + mx

where m is the slope and b the Y-intercept.

The slope m can be computed with the formula

\bf m=\displaystyle\frac{\displaystyle\sum_{i=1}^n(x_i-\bar x)(y_i-\bar y)}{\displaystyle\sum_{i=1}^n(x_i-\bar x)^2}

Replacing the values in our formula (we will round at the end of the calculations)

\bf m=\displaystyle\frac{806.94}{98,775}=0.008169476

the Y-intercept b is computed with the formula

\bf b=\bar y-m\bar x

therefore we have

\bf b=0.5188-0.008169476*26.36=0.303452613

and the least-squares line rounded to 4 decimals would be

y = 0.3035 + 0.0082x

b. Predict the warping at a temperature of 40°C. Round the answer to three decimal places.

We simply replace x with 40 to get

y = 0.3035 + 0.0082*40 = 0.6315 mm

c. At what temperature will we predict the warping to be 0.5 mm? Round the answer to two decimal places

Here, we replace y with 0.5 and solve for x

0.5 = 0.3035 + 0.0082x ===> x = (0.5-0.3035)/0.0082 ===>

 

x = 23.9634 °C

6 0
3 years ago
What is the answer to -4+x=5x+16
34kurt

Answer: x=-5

Step-by-step explanation:

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3 years ago
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