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3 years ago

If f(x) is a function and f(1) = 5, then which of the following could not be true?

Mathematics

1 answer:

vodomira [7]3 years ago

5 0

A. you are given that f(1)=5 therefore f(1) cannot also equal 1 unless it is a different equation.

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Eli read 1 book in 5 months If he read constantly how many books did he read?

Ksivusya [100]

Answer:

(life span - age when he started reading)/5months =number of books he read

Step-by-step explanation:

(life span - age when he started reading)/5months =number of books he read

5 0

2 years ago

List the steps to the following equation 5x - 6 = 44 then solve for x

Misha Larkins [42]

Add 6 to both sides so the -6 cancels out then divide the 38 you will get from 44-6 by 5 (38/5) to get your answer

5 0

3 years ago

Read 2 more answers

Can someone please help me with this logarithm equation!!

enot [183]

Answer:

$\frac{629}{2}$

Step-by-step explanation:

So, our equation is:

$log_5(\frac{2x-4}{5}) = 3$

In exponetial form, this looks like:

$5^3=\frac{2x-4}{5}$

Now lets cube the 5:

$125=\frac{2x-4}{5}$

Next, we can multiply the denominator on the right side by 5:

$625=2x-4$

We need to now get x alone by adding 4 to both sides:

$629=2x$

Finally, we divide by x's coefficent, 2, to get:

$x=\frac{629}{2}$

Hope this helps! :3

6 0

2 years ago

Barbara claims that her horse can do simple addition problems. She showed her horse eight different cards with simple addition p

Arturiano [62]

Answer:

Barbara's horse can add

Step-by-step explanation:

To test if the horse could add, Eric he tried to calculate experimentally the probability that the horse had guessed the 8 answers.

If we call "trial" the action of throwing 8 coins and count the number of tails obtained, then eric made 53 trials.

During each trial, 8 events could have occurred:

Get 1, 2, 3, 4, 5, 6, 7 or 8 tails.

The plot of points obtained by Eric shows the frequency in which each of these 8 events occurred during the 53 trials.

The fact that the point diagram shows only one point on event 8, means that it occurred only once during the 53 trials, and compared to the other 7 events, this was the one with a lower frequency (the one that obtained the the highest frequency was the 4-tailed one, with 11 points).

This means that it is very unlikely to get 8 queues when casting 8 coins.

Therefore it also means that it is unlikely that Barbara's horse has guessed the 8 answers.

So, curiously, Barbara's horse maybe knows how to add

6 0

3 years ago

Read 2 more answers

400 Suppose a particular surveillance system has a 99% chance of correctly identifying a future terrorist and a 99.8% chance of

alexgriva [62]

Answer:

1.236 × 10^(-3)

Step-by-step explanation:

Let A be the event that the person is a future terrorist

Let B the event that the person is identified as a terrorist

We are told that there are 1,000 future terrorists in a population of 400 million. Thus, the Probability that the person is a terrorist is;

P(A) = 1000/400000000

P(A) = 0.0000025

P(A') = 1 - P(A)

P(A') = 1 - 0.0000025

P(A') = 0.9999975

We are told that the system has a 99% chance of correctly identifying a future terrorist. Thus; P(B|A) = 0.99

Thus, P(B'|A) = 1 - P(B|A)

P(B'|A) = 1 - 0.99

P(B'|A) = 0.01

We are told that there is a 99.8% chance of correctly identifying someone who is not a future terrorist. Thus; P(B'|A') = 0.998

Hence: P(B|A') = 1 - P(B'|A')

P(B|A') = 1 - 0.998

P(B|A') = 0.002

We want to find the probability that someone who is identified as a terrorist, is actually a future terrorist. This is represented by: P(A|B)

We can find it from bayes theorem as follows;

P(A|B) = [P(B|A) × P(A)]/[(P(B|A) × P(A)) + (P(B|A') × P(A')]

Plugging in the relevant values;

P(A|B) = [0.99 × 0.0000025]/[(0.99 × 0.0000025) + (0.002 × 0.9999975)]

P(A|B) = 0.00123597357 = 1.236 × 10^(-3)

8 0

2 years ago