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iren2701 [21]
3 years ago
11

True or False- You can use the distributive property to help you expand and factor expressions.

Mathematics
1 answer:
vladimir2022 [97]3 years ago
8 0

Answer:

true

Step-by-step explanation:

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If z = 4.0 and y = 5.6, what is the value of x? z=y/x Express your answer to the tenths place (i.e., one digit after the decimal
liraira [26]

Answer:

x=1.4

Step-by-step explanation:

Write the equation

\frac{5.6}{x} =4

Multiply both sides by x

5.6=4x

Divide both sides by 4

1.4=x

Hope this helps! Plz award Brainliest : )

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1 11/25

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3 years ago
Which expression does NOT simplify to 1?
koban [17]

fg^3 / g^3f = 1

f^4 / f*f*f*f = f^4 / f^4 = 1

f^2g^3 / f^3g^2 = g/f

f*f/f^2 = f^2 / f^2 = 1

Answer:

f^2g^3 / f^3g^2

6 0
3 years ago
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In 2005, there are 705 cable users in the small town of Whoville. The number of users
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Step-by-step explanation:

5 0
3 years ago
The J.O. Supplies Company buys calculators from a non-US supplier. The probability of a defective calculator is 10 percent. If 3
RSB [31]

Answer:

There is a 24.3% probability that one of the calculators will be defective.

Step-by-step explanation:

For each calculator, there are only two possible outcomes. Either it is defective, or it is not. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability of a defective calculator is 10 percent.

This means that p = 0.1

If 3 calculators are selected at random, what is the probability that one of the calculators will be defective

This is P(X = 1) when n = 3. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{3,1}.(0.1)^{3}.(0.9)^{2} = 0.243

There is a 24.3% probability that one of the calculators will be defective.

3 0
3 years ago
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