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4 years ago

THE BEST ANSWER GETS BRAINLIEST

Mathematics

2 answers:

gayaneshka [121]4 years ago

8 0

6:7 is the ratio. because for every six cuos there is 7 cups of milk

ioda4 years ago

8 0

6:7 is your answer have a good day

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Help me please, you gonna be my hero

Lisa [10]

The rate of change of the relationship is 6/5

<h3>Rate of change of a line</h3>

The rate of change of a line is also known as the slope of the line. The formula for calculating the slope of a line is expressed as:

Slope =y2-y1/x2-x1

Given the coordinate points (-3,-2) and (2, 4). On substituting;

Slope = 4-(-2)/2-(-3)

Slope =4+2/2+3

Slope = 6/5

Hence the rate of change of the relationship is 6/5

Learn more on rate of change here: brainly.com/question/25184007

#SPJ1

8 0

2 years ago

12a - 6 + 7a - 2a ; a = 4 Need help please

Novosadov [1.4K]

Answer:

Step-by-step explanation:

Plug in the value of a in the equation:

12(4) - 6 + 7(4) - 2(4)

Solve 12(4) - 6:

12(4) - 6 = 48 - 6 = 42

Solve 7(4) - 2(4):

7(4) - 2(4) = 28 - 8 = 20

Combine both answers (42+20):

42+20 = 62

Complete answer:

12(4) - 6 + 7(4) - 2(4) = 62

3 0

3 years ago

Simplify. Use a horizontal format. (-2y2 - 4y - 11) + (4y2 - 4y)

dimulka [17.4K]

-4y-11 that the answer hope it helps

6 0

3 years ago

If a=4 and b=6 what is the answer 5+(6a+10b)=

nika2105 [10]

Answer:

The answer to this problem is 89.

7 0

3 years ago

Read 2 more answers

PLEASE HELP GUYS i am struggling so much, two questions

ankoles [38]

Answer: the equation of the standard parabola

1) $(y-6)^2 = 4 (x-1)$

The equation of the standard parabola

2) (x+5)^2 = 16(y-2)

Step-by-step explanation:

Explanation

Parabola:-

The set of points in a plane whose distance from a fixed point and a constant ratio to their corresponding perpendicular distance from a fixed straight line is a conic.

Let S be a fixed point and l be a fixed straight line from any point P,the perpendicular PM is drawn to the line 'l'

The locus of P such that $\frac{SP}{PM} = constant$
The fixed point 'S' is called the Focus.
The fixed line'l 'is called the directrix of the conic
The constant ratio is known as the eccentricity, denoted by 'e'
If e=1 , the conic is called a parabola

1) Step 1 :-

Given the focus S = (2,6) and directrix is x=0

we know that $\frac{SP}{PM}=1$

now cross multiplication , we get

$SP = PM$

squaring on both sides,we get

$SP^{2} = PM^2$

step 2:-

now using distance formula is

$\sqrt(((x_{2}-x_{1})^2+(y_{2} -y_{1} )^2)$

Given S =(2,6) and P(x,y) be any point on parabola

$SP^2 = (x-2)^2+(y-6)^2$ ........(1)

Now using perpendicular distance formula

let P(x , y ) be any point on the parabola

$\frac{ax_{1}+by_{1}+c }{\sqrt{a^2+b^2} }$

Given the directrix is x =0 and P(x,y) be any point on parabola

$PM^2 = \frac{x^2}{\sqrt{1}^2 }$ ......(2)

equating equation(1) and equation (2), on simplification

we get $(x-2)^2+(y-6)^2 = x^2$ .....(3)

apply $(a-b)^2 = a^2+ b^2+2 ab$

now the equation (3) is

$(y-6)^2 = 4 x-4$

now the standard form of parabola is

$(y-k)^2 = 4 a(x-h)$

Final answer:-

$(y-6)^2 = 4 (x-1)$

2) Explanation:-

step 1:

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

here the given points of 'x'co- ordinates are equal

Therefore the axis AS is parallel to y- axis

now the standard equation of parabola

$(x-h)^2 = 4 a (y-k)$

now you have to find' a' value

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

The distance of $AS = \sqrt{(-5-(-5)^2+(2-6)^2}$

on simplification we get a =4

Final answer :-

the vertex (h,k) = (-5,2) and a=4

$(x-h)^2 = 4 a (y-k)$

The standard parabola is $(x+5)^2 = 16 (y-2)$

5 0

3 years ago