Answer:
option A
Explanation:
Option A.
With the use of Administrative simplification, we can transform all the paper work to electronic media such as electronic receipts or electronic mail. By shifting towards electronic means in Administrative simplification we are actually saving a lot of time by helping the human resource and from the laborious tasks of paper work and data management.
The management of electronic means is very easy and friendly, it is also a reason for implementing administration simplification as well.
Answer:
The answer is ".pcapng"
Explanation:
Wireshark format includes a "dump" with data packets, which is collected over a channel and sometimes a common folder to store, that data in the PCAP Next Iteration file system.
- The .pcapng stands for the file system, this file system compatible with the recorded data transmission packet. It includes several data blocks.
- It is quite robust, but it should not be helped by the other devices. Wireshark allows the libpcap system as well.
Answer:
CPU scheduling is a process which allows one process to use the CPU while the execution of another process is on hold(in waiting state) due to unavailability of any resource like I/O etc, thereby making full use of CPU. ... The selection process is carried out by the short-term scheduler (or CPU scheduler).
Answer
First part:
The transmitted 8-bit sequence for ASCII character '&' with odd parity will be 00100110. Here leftmost bit is odd parity bit.
Second part:
The invalid bit sequence are option a. 01001000 and d. 11100111
Explanation:
Explanation for first part:
In odd parity, check bit of either 0 or 1 is added to the binary number as leftmost bit for making the number of 1s in binary number odd.
If there are even number of 1s present in the original number then 1 is added as leftmost bit to make total number of 1s odd.
If there are odd number of 1s present in the original number then 0 is added as leftmost bit to keep the total number of 1s odd.
Explanation for second part:
A valid odd parity bit sequence will always have odd number of 1s.
Since in option a and d, total number of 1s are 2 and 6 i.e. even number. Therefore they are invalid odd parity check bit sequences.
And since in option b and c, total number of 1s are 5 and 7 i.e. odd numbers respectively. Therefore they are valid odd parity check bit sequences.
