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emmasim [6.3K]
3 years ago
10

The following types of websites are

Computers and Technology
1 answer:
zzz [600]3 years ago
3 0
Mmm what are u talking abouy
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Follows are the solution to this question:

import java.util.*;//import package  

public class Main//defining a class

{

       public static void main(String[] ags)//main method  

       {

       float GPA;//defining floating point variable  

       int annual_income;//defining integer variable

       Scanner ga = new Scanner(System.in);//creating Scanner class object

       System.out.println("Enter GPA of student family : ");//print message

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       annual_income= ga.nextInt();//input value from user-end

      System.out.println("Is student resident of New Jersey(y/n) :");//print message

       char a=ga.next().charAt(0);//defining char variable to input char value

if(GPA>=3.75) //use if block to check GPA value

       {

        if(annual_income>60000) // use if to check annual income value

         {

            if((a == 'y'|| a== 'Y')) //use if to check char value

   System.out.println("Student accepted in college");//print message

            else//defining else block

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         }

        else//defining else block

          System.out.println("Student is not accepted in college because annual income is less than $60000 ");//print message

    }

   else//defining else block

    System.out.println("Student is not accepted in college because GPA is less than 3.75 ");//print message

       }

}

Output:

Please find the attached file.

Explanation:

Please find the attached file of the pseudocode.

In this code one integer, one float, and char variable "GPA, annual_income, and a" is declared, that uses the scanner class for accept value from the user-end, and in the next step, nested if the statement is used that checks the GPA value, annual_income, and a value and use the print method to print a value with the message.

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Its gonna be about 39%.
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