Let's simplify step-by-step.<span><span><span><span>52x</span>+<span><span>43<span>y92</span></span>x</span></span>+<span><span>3<span>y15</span></span>y</span></span>+<span><span><span><span><span><span><span><span><span>8<span>x6</span></span>x</span><span>y23</span></span>x</span><span>y6</span></span>x</span><span>y32</span></span>x</span>y
</span></span><span>=<span><span><span><span>52x</span>+<span><span>43x</span><span>y92</span></span></span>+<span>3<span>y16</span></span></span>+<span><span>8<span>x10</span></span><span>y62
</span></span></span></span>Answer:<span>=<span><span><span><span><span>43x</span><span>y92</span></span>+<span><span>8<span>x10</span></span><span>y62</span></span></span>+<span>3<span>y16</span></span></span>+<span>52<span>x</span></span></span></span>
Answer:
C.) 1 5/b boxes
Number of boxes left over
= 3 - 1/2 - 2/3
Convert each fraction to one in terms of the LCM:
= 18/6 - 3/6 - 4/6
= 11/6
= 1 5/6 boxes.
Answer:
75°
Step-by-step explanation:
1. Consider right triangle ABC. In this triangle
m∠C = 90º and CM - angle bisector.
If CM is angle C bisector, then
m∠ACM = m∠MCB = 45º
2. Consider triangle CMB. The sum of the measures of all interior angles of the triangle is always 180°, then
m∠MCB + m∠CBM + m∠BMC = 180°,
m∠BMC = 180° - 45° - 30°
m∠BMC = 105°
3. Angles AMC and BMC are supplementary angles, so
m∠AMC + m∠BMC = 180°
m∠AMC = 180° - 105°
m∠AMC = 75°
Answer:
185.68 cm3
Step-by-step explanation:
SA = 2 (L x W) + 2 (L x H) + 2 (W x H)
= 2 (8.2 x 3.4) + 2 (8.2 x 5.6) + 2 (3.4 x 5.6)
= 2 (27.88) + 2 (45.92) + 2 (19.04)
= 55.76 + 91.84 + 38.08
SA = 185.68 cm3
